2 Parallel connected cables resistance.Going from Diamater (mm) to m^2?

In summary: Unit conversions are often spelled out in the following manner, by multiplying by ratios. Each ratio has a true value of one, being the ratio of a number of units equal in "value" to some other number of units. Thus if there are one million mm2 in one meter2, then:$$2.54\; mm^2 \times \frac{1\; m^2}{10^6\;mm^2} = 2.54\times10^{-6}\; m^2$$Notice how all the work ends up being cancelling out the units from numerators and denominators and adding up the exponents. No need to muck around with decimal
  • #1
Totter
8
0
A load taking 18.2A is supplied by aluminum and copper cables connected in parallel. The lengths of the copper and aluminium cables are 78m and 64m respectively. The diameter of the aluminium 1.8mm and that of the copper 2.1mm . The resistivity abd copper is 0.018uOHMm (Ohm.meter) and 0.031uOHMm (Ohm.meter) respectively. Calculate the following:

a. The current in each cable
b. The voltage drop across each cable.
c. Power dissipation in each cable.

Now I think if I could get the total resistance of both cables I could just handle them as if they where Resistors and work out all the questions but can't seem to remember how to m^2 of the cables from their current mm reading.

Think if I could do that it would be easy to work out R with R=l.p/a formula were l = meter , a = cross section (m^2) , p = (Ohm.Meter)

Please help.
 
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  • #2
that is how you go about it. Be careful... they have given diameter and cross section area = pi r^2
 
  • #3
Ok so I came up with this..

ITS a huge mess

Aluminium Cable = R1
Copper Cable = R2
I =18.2A
R1s = 78m
R2s= 64m
R1a = r^2 π=(0.9)^2 (π)= 2.54mm^2÷1000=0.00254421m^2
R2a = r^2 π=(1.05)^2 (π)= 3.4629525mm^2÷1000=0.0034629525m^2
R1Ωm= 0.018μΩm ×〖10〗^(-6)=0.000000018Ωm
R2Ωm= 0.031μΩm ×〖10〗^(-6)=0.000000031Ωm
R1=78(0.000000018 )/((0.00000254421) )=0.9138=913.8mΩ
R2=64(0.000000031)/((0.0000034629525) )=0.332664=332.66mΩ
 
  • #4
When converting mm2 to m2 it is important to remember that there are a million square mm in a square meter; a thousand for each meter and a square meter is 1m x 1m.

Also, it looks like you've interchanged the resistivities of the metals. Copper should be the better conductor, so its resistivity should be smaller.
 
Last edited:
  • #5
Im sorry I might sound stupid but I am confused.
So you can't just go 2mm^2/1000 = 0.002m^2 ?
Should then say 2mm/1000*1000 ?
Wouldnt that just complicated question even further?

Thanks for the replies :)
 
  • #6
Totter said:
Im sorry I might sound stupid but I am confused.
So you can't just go 2mm^2/1000 = 0.002m^2 ?
Should then say 2mm/1000*1000 ?
Wouldnt that just complicated question even further?
It is what it is :smile:. No matter what it does to the question, there are a million square millimeters in a square meter! By the way, a million can be written as 106.

Scientific notation was invented to clean up all this leading zero nonsense. It's a great tool that you should get used to.
Thanks for the replies :)
Glad to be of help.
 
  • #7
So 2.54mm^2 would be 2.54mm^2 x10^-6 = 0.00000254m^2
 
  • #8
Totter said:
So 2.54mm^2 would be 2.54mm^2 x10^-6 = 0.00000254m^2

Unit conversions are often spelled out in the following manner, by multiplying by ratios. Each ratio has a true value of one, being the ratio of a number of units equal in "value" to some other number of units. Thus if there are one million mm2 in one meter2, then:

$$2.54\; mm^2 \times \frac{1\; m^2}{10^6\;mm^2} = 2.54\times10^{-6}\; m^2$$

Notice how all the work ends up being cancelling out the units from numerators and denominators and adding up the exponents. No need to muck around with decimal places.
 

Related to 2 Parallel connected cables resistance.Going from Diamater (mm) to m^2?

1. How do I calculate the total resistance of two parallel connected cables?

The total resistance of two parallel connected cables can be calculated using the formula 1/Rt = 1/R1 + 1/R2, where Rt is the total resistance and R1 and R2 are the resistances of the individual cables. This formula assumes that the cables have the same diameter and material.

2. How does the diameter of the cables affect the total resistance?

The diameter of the cables has a direct impact on the total resistance. The larger the diameter, the lower the resistance will be. This is because a larger diameter allows for a larger cross-sectional area, which reduces the resistance to the flow of electricity.

3. What units are used to measure the diameter of the cables?

The diameter of cables is typically measured in millimeters (mm). However, it is important to convert this measurement to meters (m) in order to use the correct unit for the calculation of resistance in m^2. This can be done by dividing the diameter in mm by 1000 to get the measurement in meters.

4. How do I convert the diameter of the cables to m^2?

To convert the diameter of cables from mm to m^2, you can use the formula A = πr^2, where A is the area in m^2, π is the mathematical constant pi, and r is the radius of the cable. The radius can be calculated by dividing the diameter by 2. Once you have the area, you can use it in the formula for resistance (R = ρL/A) to calculate the total resistance.

5. Can I use the same formula for calculating resistance with different materials?

No, the formula for calculating resistance (R = ρL/A) only applies to materials with a constant resistivity (ρ). Different materials have different resistivities, so the formula will vary depending on the material of the cables. It is important to use the correct formula for the specific material being used in order to accurately calculate the resistance.

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