A load taking 18.2A is supplied by aluminum and copper cables connected in parallel. The lengths of the copper and aluminium cables are 78m and 64m respectively. The diameter of the aluminium 1.8mm and that of the copper 2.1mm . The resistivity abd copper is 0.018uOHMm (Ohm.meter) and 0.031uOHMm (Ohm.meter) respectively. Calculate the following: a. The current in each cable b. The voltage drop across each cable. c. Power dissipation in each cable. Now I think if I could get the total resistance of both cables I could just handle them as if they where Resistors and work out all the questions but cant seem to remember how to m^2 of the cables from their current mm reading. Think if I could do that it would be easy to work out R with R=l.p/a formula were l = meter , a = cross section (m^2) , p = (Ohm.Meter) Please help.