2 Port analysis of series Inductor (Simple)

AI Thread Summary
The discussion focuses on calculating the S-parameters for a 2-port network consisting of a series inductor with an impedance of Z = j100 Ω in a 50 Ω system. The user successfully determines S_{22} as (1/2)(1+j) by terminating the line with the characteristic impedance, but expresses confusion over calculating S_{12}, which results in -1. This raises the question of whether a negative transmission coefficient indicates a phase shift of π. The user also mentions an alternative approach using y parameters for better understanding. Overall, the thread highlights the complexities of S-parameter calculations in RF engineering.
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EDIT: Oops! I posted this in the wrong section! Meant to post in engineering section!

I am not sure if I am doing this problem correctly or not. It is very simple.

1. Homework Statement

A 2 port network consists of just a series inductor with ##Z=j 100 \Omega## in a ##50 \Omega## system. Determine the corresponding S-parameters.

Homework Equations


S Parameter matrix equations
b_1 = S_{11}a_1 + S_{12}a_2
b_2 = S_{21}a_1 + S_{22}a_2
Where
a_1=\frac{V_1+Z_0I_1}{2\sqrt{Z_0}},
a_2=\frac{V_2+Z_0I_2}{2\sqrt{Z_0}},
b_1=\frac{V_1-Z_0I_1}{2\sqrt{Z_0}},
b_2=\frac{V_2-Z_0I_2}{2\sqrt{Z_0}}.

The Attempt at a Solution



First I let ##a_1=0## by terminating the line with an impedance equal to the characteristic impedance so ##V_1=-Z_0I_1##. Doing this allows me to use my first two equations above and solve for both ##S_{22}## and ##S_{12}##.

S_{22}=\frac{b_2}{a_2}=\frac{V_2-Z_0I_2}{V_2+Z_0I_2}=\frac{Z_{out}-Z_0}{Z_{out}+Z_0}

When the circuit is terminated on the LHS with a resistor equal to the characteristic impedance, the output impedance is simply ##Z+Z_0##. Plugging everything in, this gives me.
S_{22}=\frac{1}{2}(1+j)

This part wasn't a problem, getting ##S_{12}## is giving me confusion. The equation is, (we will use ##I_1=I_2##)
S_{12}=\frac{b_1}{a_2}=\frac{V_1-Z_0I_1}{V_2+Z_0I_2}=\frac{\frac{V_1}{I_2}-Z_0}{\frac{V_2}{I_2}+Z_0}.

Because ##a_1=0## we know that ##V_1=-Z_0I_1=-Z_0I_2##, also ##V_2/I_2=Z_0##thus,
S_{12}=\frac{-2Z_0}{\frac{V_2}{I_2}+Z_0}=\frac{-2Z_0}{2Z_0}=-1.

This is what I am confused about. Can the transmission coefficient be negative? Would that just mean that the transmitted energy simply has a ##\pi## phase shift? Am I doing this right?

The other two parameters can be obtained by similar means.
 
Since the inductor is imbedded in a Z0 = 50 ohm system you can
1. find the y parameters for the 2-port.
2. normalize to the 50 ohm environment (source and load = 50 ohms, possible xmsn line Z0 also = 50 ohms connecting the source to the input port and the output port to the load)
3. convert to s parameters using conversion tables.

This is probably not the approach used by seasoned microwave engineers but I like it because I understand y parameters better than s parameters.
 
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