2 questions one wave one delta function

AI Thread Summary
In the discussion, the first question addresses the concept of "minimum" in wave interference, specifically seeking the value of phase shift \( p \) that results in zero amplitude for the superposition of three waves. The second question involves evaluating the integral of a function multiplied by the delta function, where the user mistakenly believes it should equal zero. Clarification is provided that the integral evaluates to the function's value at the delta function's argument, leading to a result of 6, not 0. The confusion stems from misunderstanding the properties of the delta function and its application in integrals. Overall, the thread highlights key concepts in wave interference and the mathematical properties of the delta function.
Phymath
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1st question

what the heck does a "minimum" mean when talking about interference in waves, i got a question of the like y = 1.19(1 + 2 cos p)sin(kx - wt + p) is the superpostion function of three waves one which is p out of phase of the first and another which is p out of phase of the second wave. What value of p gives the minimum, i have no idea what that means I'm guessin when the amplitude is 0 or when pi/2 - kx + wt = p but how do i find that?

2nd question

i have the function

<br /> \int^{\infty}_{-\infty} (6-5x^5)\delta(x) dx

now by defintion of the delta function because 0 is contained with-in (as is all numbers) between the limits should it not = 0? thanks anyone
 
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Phymath said:
1st question

what the heck does a "minimum" mean when talking about interference in waves, i got a question of the like y = 1.19(1 + 2 cos p)sin(kx - wt + p) is the superpostion function of three waves one which is p out of phase of the first and another which is p out of phase of the second wave. What value of p gives the minimum, i have no idea what that means I'm guessin when the amplitude is 0 or when pi/2 - kx + wt = p but how do i find that?

2nd question

i have the function

<br /> \int^{\infty}_{-\infty} (6-5x^5)\delta(x) dx

now by defintion of the delta function because 0 is contained with-in (as is all numbers) between the limits should it not = 0? thanks anyone


2nd question:

Delta function:
<br /> \int^{\infty}_{-\infty} f(x)\delta(x-a) dx = f(a)
Using that, it looks to me like your value is 6
I'll look at the first question a little more before I hazard a guess on it.
 
how is it 6 when f(x) = 6-5x^4, and \delta(x) = \delta(x-0)?
 
Because the "definition" of the delta function that you refer to requires that
\int_{-\infty}^{\infty}f(x)\delta(x)dx= f(0)!
 
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