2 vibrating strings and harmonics questions

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SUMMARY

The discussion centers on calculating the tension of a second ukulele string based on its relationship with a first string vibrating at harmonics. The first string, under a tension of 60 N, vibrates at twice its fundamental frequency, equating to the second string vibrating at three times its fundamental frequency. The relevant formula used is f = (1/2L)√(T/m/L), where T represents tension and L is the length of the string. The solution involves setting the frequencies equal and solving for the unknown tension F2.

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Homework Statement


Two ukulele strings, of equal length and mass are tuned so that the first string, when it vibrates at twice its fundamental frequency, has the same frequency as the second string when
it vibrates at three times its fundamental frequency. The tension of the first string is 60 N.
Calculate the tension F2 of the second string.
Answer in units of N.


Homework Equations


f=(1/2L)Sqrt(T/m/L)


The Attempt at a Solution


so here i am stuck as i tried to set 2f1=3f2
how do i adjust for the harmonics?
 
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You can use the formula

f = \frac{p}{2L}\sqrt{\frac{T}{m/L}} where p is the number of harmonics.
 
thanks yeah i got it
 

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