2008 us physics olympiad pendulum in electric field

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The discussion revolves around solving a problem from the 2008 US Physics Olympiad regarding a pendulum in an electric field. The user struggles with understanding how to prove that the motion is simple harmonic and how to derive the period. Key points include the realization that while forces remain constant, their components change, which affects the pendulum's motion. The transformation of the coordinate system to align effective gravity with the vertical is crucial for simplifying the problem. Ultimately, the user arrives at a clearer understanding of the solution through mathematical manipulation of the forces involved.
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1. Homework Statement

i was solving the 2008 semi final us physics olympiad paper when i got stuck on question B2 in part 2
http://www.aapt.org/Programs/contests/upload/olympiad_2008_semi-final_soln.pdf
the link takes you a pdf with questions and solution however i don't understand the soution to B2 i get part ai) but not part aii) how do you prove the motion is simple harmonic and i am not sure how they derive the period in that way

Homework Equations


T = 2π/ω
f = q E
V = Ed
f = mg
sin θ ≈ tan θ ≈ θ

The Attempt at a Solution


i tried to turn the coordinate system such that the equilibrium is in a vertical position but failed miserably i also tried taking a force approach and also failed i have no idea how to start please help
 
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vishnu 73 said:
i tried to turn the coordinate system such that the equilibrium is in a vertical position but failed miserably i also tried taking a force approach and also failed i have no idea how to start please help
Please show us your attempt. If you just say that you attempted it we have no way of knowing where you went wrong.

vishnu 73 said:
sin θ ≈ tan θ ≈ θ
Note that this is true only for small angles. The way the problem is stated, there is no guarantee that ##\theta_0## or ##\theta## is small. What is small in the problem is the difference ##\theta - \theta_0##.
 
Orodruin said:
Please show us your attempt. If you just say that you attempted it we have no way of knowing where you went wrong.Note that this is true only for small angles. The way the problem is stated, there is no guarantee that ##\theta_0## or ##\theta## is small. What is small in the problem is the difference ##\theta - \theta_0##.
the problem is i know no way of how to start
i don't even how to set up the differential equation for this problem and i meant θ - θ0 is small not the actual angle itself
the reason why i say that is that because the force due to electric field and gravity are constant throughout the motion then why should there be a restoring force unlike the spring oscillator in which there is a restoring force thus there is SHM
 
Last edited:
vishnu 73 said:
the problem is i know no way of how to start
i don't even how to set up the differential equation for this problem and i meant θ - θ0 is small not the actual angle itself
the reason why i say that is that because the force due to electric field and gravity are constant throughout the motion then why should there be a restoring force unlike the spring oscillator in which there is a restoring force thus there is SHM

Well, you said that you wanted to try to write the problem in a rotated coordinate system. What do you get when you do that?

Also, the gravitational force on a standard pendulum is constant - yet it performs SHM for small angles. Do you understand why?
 
Orodruin said:
Well, you said that you wanted to try to write the problem in a rotated coordinate system. What do you get when you do that?

Also, the gravitational force on a standard pendulum is constant - yet it performs SHM for small angles. Do you understand why?

oh wait i forgot that while force remains the same the tangential components and the radial components of the force change let me try again give me some time
 
OK now i get the solution what it essentially means is that there is combined effective "gravity" pointing not directly down but at an angle of θo and then when you do the coordinate transformation such that the effective "gravity" is pointing directly down you get the equation from then on its just mathematical manipulation am i right?
 

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