What is the Intersection of Two Curves?

  • Thread starter Thread starter Jasty
  • Start date Start date
  • Tags Tags
    Curves Surface
Jasty
Messages
5
Reaction score
0

Homework Statement



y=x^2-2.x
y=x^3

Homework Equations



none

The Attempt at a Solution



I have no idea how to do this so please help me. Thank you.
 
Physics news on Phys.org
Hi Jasty! :smile:

Are you trying to find the area?

If so, divide it into slices of thickness dx, find the area of each slice, and integrate. :smile:
 
1. Draw their graphs.

2. Determine where they intersect.

3. Imagine the area divided into thin, vertical rectangles.

4. What would be the area of each of those rectangles?

5. Their total area is a Riemann sum. Convert that into an integral.
 
Thanks a lot. Finally, i found out how to deal with this one.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top