2D kinematics -- Calculate the acceleration of the jumping athlete

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SUMMARY

The discussion centers on calculating the acceleration of a jumping athlete, specifically addressing an acceleration value of 11 m/s². Participants identified an error in the initial calculations and emphasized the importance of considering the direction of the reactive force, which is "backward 55 degrees up." The conversation highlights the need for clarity in both magnitude and direction when analyzing kinematic problems in two dimensions.

PREREQUISITES
  • Understanding of 2D kinematics principles
  • Familiarity with vector components and their calculations
  • Knowledge of acceleration and its directional properties
  • Basic trigonometry for resolving forces
NEXT STEPS
  • Study vector resolution in 2D kinematics
  • Learn how to apply Newton's second law in two dimensions
  • Explore the concept of reactive forces in motion
  • Investigate the effects of angle on acceleration calculations
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Students studying physics, educators teaching kinematics, and anyone interested in understanding the dynamics of jumping and projectile motion.

Stewkatt
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Homework Statement
An athlete with a mass of 62 kg jumps and lands on his feet. The ground exerts a total force of 1.1 x 10^3 N [backward 55 degrees up] on his feet. Calculate the acceleration of the athlete
Relevant Equations
F=delta p/delta t =ma
DCD301E4-C8E1-43CD-A362-D64E05F31F14.jpeg

this is my work but the answers say 11 m/s^2 so I made an error somewhere. Also if someone could help me with solving the direction for the acceleration, that would be greatly appreciated.
 
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Perhaps because you have omitted the "backward 55 degrees up" direction of the reactive force.
 
image.jpg

yay, I figured it out. I still have to find the direction of acceleration and that’s it.
 
Stewkatt said:
yay, I figured it out. I still have to find the direction of acceleration and that’s it.
Did you find the direction of acceleration?
 

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