2D momentum of two objects next to a wall

[Jeriho]

Homework Statement

We have two pucks next to a wall. Puck 1 has velocity v₀=15 m/s in the direction y (as seen on the picture). Puck 2 is stationary. After the collision puck 1 moves in the opposite direction with velocity v₁=10 m/s and puck 2 moves with unknown velocity in the direction x. The radius of puck 1 is r₁=3cm and of puck 2 r₂=6cm. The mass of puck 1 is m₁=0.1kg and of puck 2 m₂=0.5kg. The collision is not elastic.

What is the velocity of puck 2 after the collision?

http://img134.imageshack.us/img134/8082/breznaslova.jpg

Homework Equations

Equation of momentum P=mv
Pythagorean theorem c²=a²+b²

The Attempt at a Solution

First I calculated the angle using the radiuses of the pucks and I got Cos(\alpha)=\frac{r₂-r₁}{r₂+r₁}
I got that \alpha = 70.5 degrees.

Then I went on to figure out momentums. I figured out this:
http://img256.imageshack.us/img256/8120/breznaslova2.jpg
The angle between P₀ and P₂ is \alpha.
Then I went on to make the P₁ the hypotenus and the opposite is P_1y which is the same as P=m₁v₁. From that I calculated the angle and then the adjacent P_1x. Am I right to think that the velocity I am looking for is v_x=\frac{P_1x}{m₂}.

Thanks for any assistance.

 

[Jeriho]

Does no one have an idea how to do this?

 

[Jeriho]

buuuuuuuump