[2D projectile problem]: Rocket being launched

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A rocket is launched at a 70-degree angle with a net acceleration of 8 m/s² for 6.5 seconds before entering free-fall. The initial conditions include zero speed, with calculations needed for velocities and distances at the end of the acceleration phase. After 6.5 seconds, the rocket continues to ascend until the vertical velocity reaches zero, marking the maximum height. The net acceleration accounts for gravity, simplifying the calculations. This scenario exemplifies a standard projectile motion problem following the high acceleration phase.
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Homework Statement


A rocket launched at 70 degrees to the horizontal has a constant net acceleration of 8m/s^2 along this direction for 6.5s and then is in free-fall.

Find: (a) the maximum height; (b) the horizontal range.


Homework Equations


Kinematics equations (along x and y)


The Attempt at a Solution


I know that at the initial position, along x: position=0, velocity=V0cos70 and acceleration=8cos70. along y: position=0, velocity=V0[SUB/]sin70 and acceleration=8sin70.
 
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It looks to me like the rocket initially has zero speed. It burns for 6.5 s, accelerating at 8 m/s². You'll also have to consider the acceleration of gravity during those 6.5 s. So, can you come up with the velocities and distances at the end of the 6.5 s?
 
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I got it! ... after the 6.5s, the rocket keeps moving right? till V=0?
 
Yes, the maximum height will be where Vy = 0.
It is just a standard projectile problem after the high acceleration phase.
 
Delphi51 said:
It looks to me like the rocket initially has zero speed. It burns for 6.5 s, accelerating at 8 m/s². You'll also have to consider the acceleration of gravity during those 6.5 s. So, can you come up with the velocities and distances at the end of the 6.5 s?

The problem statement says the NET acceleration is 8m/s^2, so gravity is already taken into account.
 
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