- #1
zanazzi78
- 115
- 1
Solve the following for y(x);
y'' - 3y' + 2y = 0
I kind of know what to do up to a point but after that I`m stuck (bad notes and no textbook!).
Here`s what i`ve done so far, if someone could hint as how to finish this question i should be able to do the other 9 I have.
let y = e^rx then y' = r e^rx and y''= r^2 e^rx
therefor
r^2 e^rx -3re^rx + 2e^rx = 0
or
r^2 -3r +2 = 0
or
(r-2)(r-1)=0
i.e. r=2 and r=1
now i`m stuck! What do i need to do to find the solution?
(sorry about the lack of latex but my pc refuses to display it! so if you could not use it i would be gratefull)
y'' - 3y' + 2y = 0
I kind of know what to do up to a point but after that I`m stuck (bad notes and no textbook!).
Here`s what i`ve done so far, if someone could hint as how to finish this question i should be able to do the other 9 I have.
let y = e^rx then y' = r e^rx and y''= r^2 e^rx
therefor
r^2 e^rx -3re^rx + 2e^rx = 0
or
r^2 -3r +2 = 0
or
(r-2)(r-1)=0
i.e. r=2 and r=1
now i`m stuck! What do i need to do to find the solution?
(sorry about the lack of latex but my pc refuses to display it! so if you could not use it i would be gratefull)