2nd order nonhomogeneos differential equations with initial conditions

pedro123
Messages
14
Reaction score
0
I have a problem which in involves a second order differential equations with imaginary roots and I can seem to know how to finish the problem.

d^2y/dt^2 +15y =cos 4t+2 sin t

this is what I got so far


r^2+15=0 for the homogeneous part

r=+-(√15)

Yh=C1cos√15+C2sin√15

now is where I get stuck
 
Physics news on Phys.org
You've got to use the initial conditions to solve for C1 and C2 in order to complete the homogeneous solution. Then, you get to find the particular solution for in inhomogeneous equation.
 
yes I know but can you explain how

i know i need to have a particular solution for cos 4t+2 sin t
but i don't know how to set up
 
Problems such as these should be posted in the Homework & Coursework section, not in the technical math sections. I am closing this thread.
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
Back
Top