2x + y = 8, x - z = 2. Solve by elimination and substitution

AI Thread Summary
The equations 2x + y = 8 and x - z = 2 cannot be solved for unique values of all three variables due to having two equations with three unknowns. However, y and z can be expressed in terms of x, leading to the relationships y = 8 - 2x and z = x - 2. This results in parametric equations where any solution (x, y, z) can be represented as (x, 8 - 2x, x - 2). The solutions form a line in three-dimensional space, specifically passing through the points (0, 8, -2) and (2, 4, 0). The discussion emphasizes the importance of clarity and correctness in mathematical communication.
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Homework Statement



2x + y = 8, x - z = 2. Solve by elimination and substitution

Homework Equations



2x + y = 8, x - z = 2

The Attempt at a Solution



It cannot be solved by elimination or substitution.
 
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You can solve for y and z in terms of x.
 
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To add to LCKurtz's response, you have two equations with three variables. You can solve for any of the following:

  • x and y in terms of z
  • x and z in terms of y
  • y and z in terms of x
But you cannot solve for all three.
 
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What I would do is say that, from the first equation, y= 8- 2x, and from the second equation, z= x- 2.

That is, any (x, y, z) satisfying these equations is of the form (x, 8- 2x, x- 2).

Or if you prefer "parametric equations", (x, y, z) satisfies those equation if and only if x= t, y= 8- 2t, and z= t- 2. Those points lie on a straight line in "three-space". Geometrically, a line is determined by two points. This line is the line that passes through (0, 8, -2) and (2, 4, 0).
 
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Oops! My "correction" was erroneous.

Apologies.
 
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oay said:
z=x+2

If you want to add knowledge, please don't confuse matters by getting basic things wrong.

Everything HallsofIvy said was 100% correct. Where do you think he was wrong?
 
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Ray Vickson said:
Everything HallsofIvy said was 100% correct. Where do you think he was wrong?
Correct. Sorry to both you and HoI.
 
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