3 balls in a moving mechanics problem

Click For Summary
The discussion revolves around a mechanics problem involving three balls connected by ropes, where two balls (A and B) move horizontally while a third ball (G) descends. Participants express confusion about the forces acting on the system, particularly regarding the tension in the ropes and the application of energy conservation principles. Key points include the relationship between the accelerations of the masses and the need to derive equations of motion based on free body diagrams. The conversation emphasizes that the time of impact depends on the initial distance between A and B, and while some participants claim to have solved parts of the problem, others continue to seek clarification on the time of collision. Ultimately, the discussion highlights the complexities of analyzing the system's dynamics and the importance of understanding the underlying physics principles.
  • #31
I do not consider the time I gave freely to you wasted. If you are willing to pick up at post #26 and reconsider your expressions for the initial and final potential energy, please do so and I will continue guiding you. If not, not.
 
Physics news on Phys.org
  • #32
kuruman said:
I do not consider the time I gave freely to you wasted. If you are willing to pick up at post #26 and reconsider your expressions for the initial and final potential energy, please do so and I will continue guiding you. If not, not.
are you sure conservation will lead me to finding the time of impact?
 
  • #33
Manolisjam said:
are you sure conservation will lead me to finding the time of impact?
some1 else told me to llok at the relaton between the accaleration o A in x axes withs its component to the direction AG and then the relation between Gs accelaration and that component
 
  • #34
kuruman said:
I do not consider the time I gave freely to you wasted. If you are willing to pick up at post #26 and reconsider your expressions for the initial and final potential energy, please do so and I will continue guiding you. If not, not.
Ok I am trying to do what you said i get the same with i did already .what is different? MY potential energy was zero when G was at L distance so if its zero at the same height i sa the final potential energy is the initial i found.
 
  • #35
kuruman said:
I do not consider the time I gave freely to you wasted. If you are willing to pick up at post #26 and reconsider your expressions for the initial and final potential energy, please do so and I will continue guiding you. If not, not.
Laso could you classify the diffculty of the problem 1-10. for a math undergrad .
 
  • #36
kuruman said:
I do not consider the time I gave freely to you wasted. If you are willing to pick up at post #26 and reconsider your expressions for the initial and final potential energy, please do so and I will continue guiding you. If not, not.
Solved it!
 
  • #37
Manolisjam said:
Solved it!
This is a duplicate of
https://www.physicsforums.com/threads/classical-mechanics-problem-with-balls.940763/
@Manolisjam , please do not duplicate threads to garner a wider audience. If you wish to bring others in you can either use the "@" link to bring in specific people, or ask your current respondent (me, in this case) to do it. Or even "report" the thread to the mentors.

Anyway, you claim to have solved it, and I think that may be true for the collision velocity if you figured out how to write the energy equation correctly, but I do not see how you will have found the time that way.
Have you found time to collision?
 
  • #38
haruspex said:
This is a duplicate of
https://www.physicsforums.com/threads/classical-mechanics-problem-with-balls.940763/
@Manolisjam , please do not duplicate threads to garner a wider audience. If you wish to bring others in you can either use the "@" link to bring in specific people, or ask your current respondent (me, in this case) to do it. Or even "report" the thread to the mentors.

Anyway, you claim to have solved it, and I think that may be true for the collision velocity if you figured out how to write the energy equation correctly, but I do not see how you will have found the time that way.
Have you found time to collision?
At the 0 point using conservation energy i get something like u_a^2+u_g^2=2gsinθl now i know dx/dt=u_a=lsinθdθ/dt . find same way u_G now squaring those. andi plugging them in conservation i get Ldθ/dt=sqrt(2sinθ) this is a differential eq separable. find θ(t) and solve for θ=π/2 but i can't solve the integral
 
  • #39
Manolisjam said:
At the 0 point using conservation energy i get something like u_a^2+u_g^2=2gsinθl now i know dx/dt=u_a=lsinθdθ/dt . find same way u_G now squaring those. andi plugging them in conservation i get Ldθ/dt=sqrt(2sinθ) this is a differential eq separable. find θ(t) and solve for θ=π/2 but i can't solve the integral
if you can show me another way for the time. i still haven't understant what you are trying to help me do.
 
  • #40
Manolisjam said:
if you can show me another way for the time. i still haven't understant what you are trying to help me do.
Ok, you have found another route to the same equation. (Your final equation is not quite right: check the powers of L and g in it.)
In case it helps in future, if two objects remain a constant distance apart then they must have the same velocities and accelerations along the line joining them. Hence aAcos(θ)=aGsin(θ).
I'll get back to you on solving the integral.
 
  • #42
haruspex said:
It seems to involve elliptic integrals. Nasty.
Yes, it is nasty. It's a bit simpler if all masses start from rest and along the horizontal line through the origin, but still an elliptic integral. Considering that OP is a math undergrad, this is perhaps a math exercise that assumes understanding of physics to get to the math. I would be curious to see what the solution is according to the person who assigned the problem.
 

Similar threads

  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 27 ·
Replies
27
Views
654
Replies
6
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 38 ·
2
Replies
38
Views
4K
  • · Replies 22 ·
Replies
22
Views
6K
Replies
6
Views
2K
Replies
8
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K