3 Blocks Create a Tension Force- Find Acceleration

AI Thread Summary
The discussion revolves around calculating the acceleration of a 2.6 kg block affected by kinetic friction on a table. The coefficient of kinetic friction is given as 0.28, and the user attempts to apply Newton's second law by analyzing forces acting on three blocks. A misunderstanding arises regarding the tension forces acting on the middle block, leading to an incorrect high acceleration value. Clarification is provided that two distinct tension forces must be considered for accurate calculations. The user contemplates whether to incorporate a third equation to ensure consistent acceleration across the blocks.
Phoenixtears
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Homework Statement


The coefficient of kinetic friction between the m = 2.6 kg block in Figure P8.35 and the table is 0.28. What is the acceleration of the 2.6 kg block? (The image is attached)
______m/s2


Homework Equations



Fk= (Mu)(N)
2nd Law statements

The Attempt at a Solution


I began by drawing three force diagrams, one for each block. Using the 2.6 and 3 blocks I wrote out 2nd law statements (because the block is shifting right), and substituted in variables for the friction forece equation:

Ca= T- Cg
Ba= T- Fk
Fk=(Mu)(Bg)... (According to my force diagrams , normal force equals weight force)

Then I sovled for T on the first equation. Substituting that in for T in the second, and replacing the Fk with the other equation:

Ba= Ca+ Cg- (Mu)(Bg)

I then solved for a. After plugging in all the numbers, I got a very high number as my a. Near 55, if I recall. What exactly did I do wrong?
 

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Phoenixtears said:
Then I sovled for T on the first equation. Substituting that in for T in the second,
The tension is different for each rope. (If not, there would be no net force on the middle block.)
 
Doc Al said:
The tension is different for each rope. (If not, there would be no net force on the middle block.)

But, according to the 3rd law, the tension between the 3 block and the 2.6 block would be equal. So why would the substitution not work?

Thanks in advance!
 
Phoenixtears said:
But, according to the 3rd law, the tension between the 3 block and the 2.6 block would be equal.
Right, I misinterpreted what T you were talking about.
So why would the substitution not work?
Because there are two tension forces on the middle block.

Phoenixtears said:
Ba= T- Fk
You left out one of the tension forces.
 
Doc Al said:
Because there are two tension forces on the middle block.


You left out one of the tension forces.

Right. That makes sense. I suppose I'm thinking horizontally (a different problem I had to do). Thank you! Now, is it possible to include the third equation? Or should I just do the two separately. My fear is that the accelerations won't equal. I'll try it out right now.
 
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