3 consecutive loops with one being moved from the other two. Len'z Law

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The discussion focuses on determining the direction of induced currents in two stationary loops (A and B) when a middle loop moves towards an observer with an anticlockwise current. According to Lenz's Law, Loop A will induce an anticlockwise current to create a north pole facing the middle loop, opposing the change. Conversely, Loop B will induce a clockwise current to generate a south pole, opposing the effective south pole of the middle loop as it moves away. The participant expresses uncertainty about their reasoning due to a lack of guidance from their teacher. Overall, the application of Lenz's Law is crucial in predicting the induced currents in the stationary loops.
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Homework Statement



Three wire loops and an observer are positioned as shown in the figure below.
From the observer’s point of view, a current I flows anticlockwise in the middle
loop as that loop moves towards the observer with a velocity of v ms^-1

zvwwv4.jpg


Loops A and B remain stationary.

In what direction are the induced currents in Loops A and B

Homework Equations



None, use Lenz's Law

The Attempt at a Solution


Using the right hand grip rule for solenoids, i got the effective N pole of the middle loop to be directed to the left, i.e directed towards the observer.

So Loop A would want to create a N pole in the direction of the middle loop to oppose the change, which using the right hand grip rule for solenoids again, means the current would be flowing anticlockwise.

Loop B would want to create a S pole to oppose the change made by the effective south pole of the middle magnet moving away from it. So the induced current would also be clockwise.

I really don't have much of a clue whether I am right, i tried to give it to my teacher but he's worse at physics than half of our class so that was a bit pointless. Anyway any help will be appreciated.
 
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If there's a N pole on the left side of the middle loop you would want a N pole on the right side of loop A and the left side of loop B.
 
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