3 point charges on the vertices of an equilateral triangle

AI Thread Summary
When the charges at the vertices of an equilateral triangle are doubled, the force between each pair of charges increases due to Coulomb's law. The equation F = k(q1*q2)/r^2 shows that force is directly proportional to the product of the charges. By doubling each charge, the new force becomes F = k(2q1*2q2)/r^2, resulting in a force that is four times greater. This increase occurs because the distance remains constant while the charges are increased. Thus, the resulting force on each charge is quadrupled.
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Homework Statement



3 equal point charges on the vertices of a triangle. If the each of the charges are doubled, why is the resulting force on each charge quadrupled?

Homework Equations



F= Fx +Fy

F= kqk2/r^2


The Attempt at a Solution


I got doubled
 
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well the force acting on charged particle (Coulomb's law) is equal to:
F=k\frac{q_1 q_2}{r^2}
if distance is left same, and charges is doubled, you get:
F=k\frac{2q_1 2q_2}{r^2}=4k\frac{q_1 q_2}{r^2}
so the force is bigger four times
 
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