Proofing that All Arcs of a Circle = 360 Degrees

AI Thread Summary
The discussion centers on proving that all arcs of a circle sum to 360 degrees, paralleling the established fact that the angles of a triangle total 180 degrees. Participants express the need for a solid motivation for each step in the proof, emphasizing that simply stating "a lap is 360 degrees" lacks depth. There is acknowledgment that while the 360-degree system is standard, alternative systems, such as a 400-degree system, have existed. The importance of maintaining a structured approach in proofs is highlighted, particularly in educational contexts. Ultimately, the conversation underscores the need for clarity and justification in mathematical proofs.
Dousin12
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Im doing a proof. For instance all sums of a triangle add upp to 180 degrees. But how to i motivate that all arcs on a circle add up to 360 degrees.

A part of my proof is that Arc A + B + C = 360 degrees.

But i don't know what to write in the column that motivates every step. ! Like a lap is 360 degrees dosent sound good enough
 
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Usually we just say, angles at a point sum to 360o
I think that is a definition of degrees.
 
Dousin12 said:
Im doing a proof. For instance all sums of a triangle add upp to 180 degrees. But how to i motivate that all arcs on a circle add up to 360 degrees.

A part of my proof is that Arc A + B + C = 360 degrees.

But i don't know what to write in the column that motivates every step. ! Like a lap is 360 degrees dosent sound good enough
In future posts, please don't delete the homework template. Its use is required.
 
Merlin3189 said:
Usually we just say, angles at a point sum to 360o
I think that is a definition of degrees.

Very much this.
 
pasmith said:
Very much this.

This is true. We have chosen to use a 360degree system for a circle but other systems like a 400 degree system (have) exist(ed) as well.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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