3a, add +b and then cube the entire thing?

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The discussion revolves around manipulating a cubic polynomial by multiplying it by 3a, adding +b, and cubing the entire expression. Participants clarify the term "cubic formula," with one suggesting it refers to the general solution for cubic equations. The conversation emphasizes the importance of starting with a clear cubic polynomial and applying algebraic operations correctly. A link to the cubic formula is provided for reference. The focus remains on understanding the algebraic transformations involved in the problem.
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A quick question... what is the resultant expression if you multiply the cubic formula by 3a, add +b and then cube the entire thing?

Much appreciated
 
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Frogeyedpeas said:
A quick question... what is the resultant expression if you multiply the cubic formula by 3a, add +b and then cube the entire thing?

Much appreciated

Pi.

Cool problem. Thanks.
 
berkeman said:
Pi.

Cool problem. Thanks.

Aside from delicious pi, have you tried just writing the equation of a cubic polynomial down and then doing your operations using normal algebra?
 
To clarify, what do you mean by "the cubic formula"? chiro seems to think you mean just a cubic polynomial. Is that correct?
 
I'm trying to rewrite the cubic formula (the general solution for the roots of a cubic polynomial into the form (3ax +b)^3 = ...

Where normally given a cubic polynomial equation

ax^3 + bx^2 + cx + d = 0

The answer can be found by making the substitution:

a = b/a

b = c/a

c = d/a

and then the formula is in this link:

http://planetmath.org/encyclopedia/CubicFormula.html
 
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