3D Harmonic Oscillator Circular Orbit

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Homework Help Overview

The discussion revolves around the concept of radial probability density in the context of a 3D harmonic oscillator, specifically referencing a text by Binney. Participants are examining the relationship between the radial probability density and the normalized wavefunction.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions the presence of an additional factor of r² in the radial probability density, suggesting that it should simply be the square of the normalized wavefunction. Other participants provide insights into the integration process in spherical coordinates, indicating where the r² factor originates.

Discussion Status

Participants are actively exploring the mathematical foundations of the radial probability density. Some have provided explanations regarding the integration in spherical coordinates, while others affirm the correctness of the presented reasoning. There is no explicit consensus yet, but the discussion is progressing with relevant contributions.

Contextual Notes

Participants are working within the framework of quantum mechanics and spherical coordinates, discussing the implications of the wavefunction and its normalization in the context of probability density.

unscientific
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Homework Statement



I found this in Binney's text, pg 154 where he described the radial probability density ##P_{(r)} \propto r^2 u_L##

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Homework Equations





The Attempt at a Solution



Isn't the radial probability density simply the square of the normalized wavefunction, |ψ(x)|2? Why is there an additional factor of r2?
 
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When you integrate a function over a volume in spherical co-ordinates you integrate over r2sin(θ)drdθdø . The sin(θ)dθdø goes into the angular function and the r2dr into the radial function. I believe this is where it comes from.
 
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BOYLANATOR said:
When you integrate a function over a volume in spherical co-ordinates you integrate over r2sin(θ)drdθdø . The sin(θ)dθdø goes into the angular function and the r2dr into the radial function. I believe this is where it comes from.
Probability = ##<\psi|\psi> = \int \psi^*\psi d^3r = \int \psi^*\psi r^2 dr d\Omega##

Where the wavefunction corresponding to the ket ##|\psi>## is ##u_L Y_l^m##

I think that's right.
 
Last edited:
unscientific said:
Probability = ##<\psi|\psi> = \int \psi^*\psi d^3r = \int \psi^*\psi r^2 dr d\Omega##

Where the wavefunction corresponding to the ket ##|\psi>## is ##u_L Y_l^m##

I think that's right.

Correct.
 

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