3rd order derivatives in the lagrangian

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I heard that in classical field theory, terms in the Lagrangian cannot have more than two derivatives acting on them. Why is this?

In quantum field theory, I read somewhere that having more than two derivatives on a term in the Lagrangian leads to a violation of Poincare invariance. Is this true?

One thing I derived is that, for a scalar field, if you accept the canonical commutation relations as true:

<br /> [\phi(x,t),\Pi(y,t)]=i\delta^3(x-y)<br />

then unless your canonical momentum \Pi(x,t) is equal to \dot{\phi}(x,t), then the commutation relations of the Fourier components of \phi(x,t) no longer obey equations like:

<br /> [a(k,t),a^\dagger(q,t)]=\delta^3(k-q)<br />

or using a different normalization scheme:

<br /> [a(k,t),a^\dagger(q,t)]=\delta^3(k-q)(2\pi)^32E_k<br />
 
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P.17 of Zee states this is because 'we don't know how to quantize actions with more than two time derivatives'. Why this is mathematically I do not know though (and was wondering the same thing myself...).
 
I found this in a book by some guy named Pierre Ramond, "Field Theory a Modern Primer".

"Third we demand that S [the action] leads to classical equations of motions that involve no higher than 2nd-order derivatives. Classical systems described by higher order differential equations will typically develop non-casual solutions. A well-known example is the Lorentz-Dirac equation of electrodynamics. It is a 3rd-order differential equation that incorporates the effects of radiation reaction and shows non-casual effects such as preacceleration of particles yet to be hit by radiation."

But this bugs me. I thought as long as your Lagrangian density is Lorentz-invariant, then the equations of motion will be Lorentz-invariant. So how can an equation that is Lorentz-invariant be non-causal?
 
The 2nd derivatives are actually first derivatives --- just integrated by parts. It is easier to consider non-field theory, but just a single particle. The Lagrangian is a function of position and velocity, and a "third derivative" would actually be a dependence on the 2nd derivative. Then see: http://www.tcm.phy.cam.ac.uk/~gz218/2010/01/higher-derivative-theories.html

In general, higher derivative theories require some exceptional fine-tuning to make sense.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!

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