4d Cartesian to Polar Transform

AI Thread Summary
The discussion focuses on the challenge of deriving a Cartesian to polar transform for \mathbb{R}^4, building on known transformations for \mathbb{R}^2 and \mathbb{R}^3. The participant expresses difficulty in visualizing angles in higher dimensions, which complicates the transformation process. They propose a potential conversion formula involving variables w, x, y, z, and r with angles theta, phi, and psi. The need for clarity and assistance in confirming this transformation is emphasized. Overall, the quest for a clear understanding of the 4D polar transformation remains a central theme.
chasehusky
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Howdy everyone,

I'm on a quest for something that is proving a bit elusive at the moment: a Cartesian to polar transform (along with its inverse) for \mathbb{R}^4. I'm well aware of how to derive the transform for both \mathbb{R}^2 and \mathbb{R}^3, as it is just a matter of looking at the angles made, with respect to the origin and appropriate coordinate axes, for the vector in question; e.g., for the \mathbb{R}^3 case: x = r \sin(\theta)\cos(\psi), y = r \sin(\theta)\sin(\psi), z = r \cos(\theta). Unfortunately, as with all high-dimensional spaces, visualizing these angles becomes much trickier. If anyone can help me with this, I'd greatly appreciate it.
 
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Well, after toying around a bit, it appears that the conversion would go something like: w = r\sin(\theta)\sin(\psi)\cos(\phi), x = r\sin(\theta)\sin(\psi)\sin(\phi), y = r\sin(\theta)\cos(\psi), z = r\cos(\theta).
 
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