500 ohm resister fed from 120 VP-Pac source

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To determine the heat dissipated by a 500-ohm resistor fed by a 120 V peak AC source, the relevant formula for power dissipation is P = V²/R. For a sine wave, the effective voltage is V_rms = V_peak/√2, leading to a power dissipation of approximately 7.2 watts. In a square wave scenario, the peak voltage is equal to the RMS voltage, resulting in a power dissipation of 14.4 watts. Understanding these calculations is crucial for students transitioning from DC to AC circuits. Mastery of these concepts will enhance comprehension of basic electrical principles.
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Homework Statement


a 500 ohm resister is fed by 120 Volt P-Peak ac source;How much heat does the resister dissipate if the signal is a sine wave or a square wave?


Homework Equations





The Attempt at a Solution

 
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What's the equation for power dissipated by a resistor?
 
I don't know I just started this course and what happened is they offered an ac circuts short course with no prerequisites and actually all but three of us have been in the class under DC circuts for three months now, we are so behind and we really want to understand and it's a ***** when your so uninformed about basic formulas and such, I refuse to give up so, no I don't know what that equation is all the quest wants is how much neat is lost when 120 volts peak is put across a circute with a 500 ohm resister in it and how much is lost in a sine wave or a square wave?
 
If it were a DC circuit, what would be the power dissipated given that the potential difference across the resistor is V?
 

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