Tension in the rope of tug of war

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In a tug of war with five men on each team pulling with an average force of 500 N, the tension in the center of the rope is 500 N, as the forces exerted by both teams are equal and opposite, resulting in a balanced tension. The initial confusion about whether the forces cancel out is clarified by understanding that tension exists in the rope due to the pulling forces. If one team is replaced with a spring scale, the reading on the scale would reflect the force exerted by the remaining team, which would still be 500 N if they are pulling with the same force. The scenario illustrates the principles of tension and force balance in a static system. Understanding these concepts is crucial for solving similar physics problems.
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Homework Statement


In a tug of war, five men on each team pull with an average force of 500 N each. What is teh tension in the center of the rope.
A. zero B. 100N C. 500N D. 2500N E.5000N

Homework Equations





The Attempt at a Solution


I know this isn't a very complicated question but I am not sure how the two forces on each side would effect it. T first i though they would cancel out, but there has to be some tension, so are they compounded? I am really unsure. Any explanation would be greatly appreciated.

Also sorry if this is in the wrong section
 
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Suppose you broke the rope in the middle, and replaced one of the teams, together with their half rope, with a spring scale (like the ones they use to weigh vegetables in a supermarket) nailed to a rigid post. Would it matter whether the spring and post were supplying the force to hold the other team in place? What would be the reading on the spring scale?
 

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