A baseball is thrown straight up with initial speed

AI Thread Summary
When a baseball is thrown straight up with an initial speed v(o), air resistance causes it to lose kinetic energy, resulting in a lower speed upon return to its initial height. The presence of air resistance converts some of the kinetic energy into thermal energy, which is why the ball does not return with the same speed. In projectile motion, the angle of projection affects the distribution of kinetic energy between vertical and horizontal components, influencing the maximum height achieved. The horizontal velocity remains constant, but the vertical velocity is affected by air resistance, leading to different maximum heights for various angles. Overall, air resistance plays a significant role in energy loss and affects the ball's motion.
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A baseball is thrown straight up with initial speed v(o). If air resistance cannot be ignored, when the ball returns to its initial height its speed is less than v(o). Explain why, using energy concepts.
I am very confused as to why this is.

A projectile has the same initial kinetic energy no matter what the angle of projection. Why doesn't it rise to the same maximum height in each case?

Is it because the velocity in the x-direction is different?
 
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If air resistance cannot be ignored,

What happens when the ball travels through the air?¨
Also, if the ball is thrown straight up the x-coordidate will not change.
 

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