A boat being pulled by two other boats with cables

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SUMMARY

The discussion centers on calculating the drag force on a boat being pulled by two other boats using trigonometric functions. The calculated drag force is 6128 N based on the formula 2(4000)cos(40°), while the provided answer states it is 6200 N. Participants highlight potential rounding errors in the answer and emphasize the importance of accurate free-body and vector diagrams for solving the problem. The conversation also critiques the accuracy of the diagrams presented, noting discrepancies in angle representation.

PREREQUISITES
  • Understanding of trigonometric functions, specifically cosine and sine.
  • Familiarity with free-body diagrams and vector representation.
  • Basic knowledge of force calculations in physics.
  • Experience with spreadsheet calculations for numerical analysis.
NEXT STEPS
  • Study the principles of free-body diagrams in physics.
  • Learn how to accurately draw and interpret vector diagrams.
  • Research rounding errors in numerical calculations and their impact on results.
  • Explore advanced trigonometric applications in force analysis.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and force analysis, as well as educators looking for examples of common calculation errors in physics problems.

Lay1
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Homework Statement
A ship is pulled at a constant speed by two small boats, A and B, as shown in Figure 4.27. The engine of the
ship does not produce any force. The tension in each cable between A and B and the ship is 4000 N.
a. Draw a free-body diagram showing the three horizontal forces acting on the ship.
b. Draw a vector diagram to scale showing these three forces and use your diagram to find the value
of the drag force on the ship
Relevant Equations
Fx = Fcos n
Fy = Fsin n
FAx = F cos 40
FAy = F sin 40
2FAx = Drag
Drag = 6128N
The answer says 6200N
 

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Your solution looks like one of those things you get during an eye test when the letters get smaller and smaller until you can't read them!
 
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My spreadsheet says ##2*4000\cos(40) = 6128##.
 
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Lay1 said:
Drag = 6128N
The answer says 6200N
I think it should be 2(4000)cos40=6128.35N (40 degree)
It is better to share a picture from the answer which suggests it's 6200N.
 
The answer to me looks like one of those cases where the answer has rounded the intermediate result from 3064 N to 3100 N and then multiplied the rounded result by two, resulting in an erroneous rounding to 6200 N instead of 6100 N for the final result.
(Also note that 6128 N is too many significant digits given the precision of the input.)
 
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PeroK said:
Your solution looks like one of those things you get during an eye test when the letters get smaller and smaller until you can't read them!
This is what happens when one only cancels one out of two subscript tags ... 😏
 
Lay1 said:
Homework Statement
a. Draw a free-body diagram showing the three horizontal forces acting on the ship.
b. Draw a vector diagram to scale showing these three forces and use your diagram to find the value of the drag force on the ship
a) You haven't shown your answer to part a).

b) From the question's wording, it looks like you are expected to solve the problem using a scale diagram (not by using trig'). You need a pencil, paper, ruler and protractor. Don't forget to label the diagram appropriately, write the scale you are using, and give your working.
 
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The diagram shown by the OP is quite inaccurate. The angles look like <30 degrees. This will lead to confusion
 
hutchphd said:
The diagram shown by the OP is quite inaccurate. The angles look like <30 degrees. This will lead to confusion
Since the student is asked to draw an accurate diagram, the book diagram will be deliberately a little inaccurate.
 
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  • #10
PeroK said:
Your solution looks like one of those things you get during an eye test when the letters get smaller and smaller until you can't read them!
I don't know why it turns out like that also.
 
  • #11
Orodruin said:
This is what happens when one only cancels one out of two subscript tags ... 😏
PeroK said:
My spreadsheet says ##2*4000\cos(40) = 6128##.
Thanks. Next time I will be careful about the words.
 

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