A bullet strikes a wooden block

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A 25 g bullet fired at 150 m/s embeds itself in a 2.0 kg wooden block, which then swings to a height of 0.175 m after the collision. The conservation of momentum equation m1v1 = (m1+m2)vf was used to find the final velocity (vf = 1.85 m/s) of the block and bullet system. The potential energy equation 1/2 mv^2 = mgh was applied to calculate the height reached. The length of the string does not affect the height unless it exceeds twice the string length. The discussion emphasizes the importance of understanding the physics concepts rather than just plugging in numbers.
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Homework Statement


A 25 g bullet is fired at 150 m/s into a 2.0 kg block of wood hanging from a string 3.0 m long. The bullet becomes embedded in the block. To what height do the bullet and block swing?


Homework Equations


m1v1 = (m1+m2)vf
1/2 mv^2 = mgh



The Attempt at a Solution


0.025 (150) = (0.025 + 2)vf
vf = 1.85 m/s

1/2 2.025 1.85^2 = 2.025 9.8 h
h = 0.175 m

I don't know what to do from here.
 
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First things first, try not to plug in numbers until after you get the final result. This reduces rounding error and can give you let you see how to do some of the algebra without having to deal with specific numbers.
That being said, you seem to have done everything right. What do you mean "I don't know that to do from here." You were told to find the height and you found the height.
 
So the length of the string doesn't matter?
 
Yes. It would only matter if the height is more than twice the string length. If it then wants you to calculate the maximum angle or the oscillation frequency, then the string length would also matter.
 
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