A bunch of functions inside of functions

[EricPowell]

Homework Statement

Find $$f'(-1)$$, given $$f(y) = h(g(y)), h(2) = 55, g(-1) = 2, h'(2) = -1$$, and $$g'(-1) = 7$$.

Homework Equations

Maybe the chain rule?

The Attempt at a Solution

I thought that I could create a function given that $$g(-1)=2$$, so I thought maybe the function could be $$g(x)=-2x$$. But if I differentiate that, I get $$g'(x)=-2$$, and obviously that doesn't work since putting -1 into $$g'(x)=-2
\\
g'(-1)=-2≠7$$. I don't know what to do.

 

[CAF123]

I don't know what to do.

Apply the chain rule to the function $f(y) = h(g(y))$.

 

[Mark44]

And after you find f'(y), evaluate f'(-1).