A Conceptual Question on de Rham cohomology.

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Discussion Overview

The discussion centers around the properties of de Rham cohomology, specifically addressing why the cohomology group H rD(M) equals zero for r greater than the dimension n of the manifold M. Participants are exploring definitions and properties related to cohomology, including cocycles and coboundaries.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions the reasoning behind H rD(M) = 0 for r > n, stating it is not obvious to them.
  • Another participant asks for clarification on how the group is defined, indicating a need for foundational understanding.
  • A subsequent post reiterates the definition of the group as HrD(M) = Ker(dr)/Im(dr-1), seeking further clarification on the homomorphism properties of dr.
  • It is suggested that the properties of the wedge product may provide insight into the question raised.
  • One participant points out that there are no non-zero cochains in dimensions above the manifold's dimension, linking this to the determinant of matrices with rank less than n.
  • Another participant emphasizes the importance of defining n-cocycles and n-coboundaries to understand the cohomology groups, referencing Poincaré Duality conditions for further clarification.

Areas of Agreement / Disagreement

The discussion reflects a lack of consensus on the initial question regarding H rD(M) = 0 for r > n, with participants offering various perspectives and seeking clarification on definitions and properties without reaching a definitive conclusion.

Contextual Notes

Participants highlight the need for clear definitions of cochains, cocycles, and coboundaries, as well as the implications of dimensionality in the context of cohomology, indicating that assumptions about these concepts may not be universally understood.

T_Mart
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Hi everybody,

Currently, I am studying cohomology on my own. I have a question:

Why H rD(M) = 0, when r > n

n is the dimension of manifold M
My book says it is obvious, but to me it is not obvious.

I wish someone could explain this question to me.
 
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Well, how is the group defined?
 
Hurkyl said:
Well, how is the group defined?

The group is defined as
HrD (M) = Ker(dr)/Im(dr-1)
 
T_Mart said:
The group is defined as
HrD (M) = Ker(dr)/Im(dr-1)

And what groups is dr a homomorphism from and to?
 
it follows from properties of the wedge product, as is being suggested.
 
How do you define n-cocycles and n-coboundaries?
 
there aren't even any ≠0 cochains in dimensions above the dimension of the manifold.

the reason is essentially that an nbyn determinant is always zero if the matrix has rank < n.
 
Yes, that was the point I was trying to make. Look up the definition of n-cocycles and n-coboundaries to see what the cohomology groups are . Or, if you have the right conditions for Poincare Duality, see why you cannot have (n+k)-cycles; k>0, in an n-manifold.
 

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