- #1
chowder
- 3
- 0
This is not my day.
Solve for x.
1.) 9^2x+1 = 27
2.) 10^5x = 1000
Thanks again!
Solve for x.
1.) 9^2x+1 = 27
2.) 10^5x = 1000
Thanks again!
You should use logarithm to solve the problems above.chowder said:This is not my day.
Solve for x.
1.) 9^2x+1 = 27
2.) 10^5x = 1000
Thanks again!
The equation is a system of two equations: 9^2x+1=27 and 10^5x=1000.
"Unsolved" means that the equations have not yet been solved for the variable x.
The goal is to find the value(s) of x that satisfy both equations and make them true statements.
The equations can be solved using algebraic manipulation, logarithms, or graphing.
Yes, there can be multiple solutions for x in each equation, but only one value of x that satisfies both equations simultaneously.