A few conceptual problems with moments

AI Thread Summary
Applying a force on a beam with its center of gravity at the midpoint will primarily create a moment without causing downward motion. If the fixed point is removed and no other forces are acting, the force will lead to acceleration rather than just a moment. The nature of the force's direction is crucial in determining the resulting motion, as it can influence whether the beam rotates or shifts. A force can indeed cause both rotational and translational motion, depending on its application angle. Clarifying the definitions and conditions of the force and moment is essential for accurate analysis.
mHo2
Messages
30
Reaction score
0

Homework Statement


My questions are as follows:
(1) If I apply a force (B) on a beam with a center of gravity at the middle(A), it will JUST cause a moment, correct?
(2) If I remove this fixed point(A), and no gravity or any other forces are present, will it still JUST cause a moment or will it cause a shift?
(3)Can a force be applied on this beam to cause a moment & a movement?


Homework Equations



kDGjZ.png


The Attempt at a Solution



I think,
(1) It will just cause a moment, not a downwards motion
(2) It will either just cause an acceleration or just a moment
(3) If I move the force along an angle, it will cause both
 
Physics news on Phys.org
It depends on how you define 'moment'. From the way your questions are worded, it looks like you are defining 'moment' to be a rotational motion around the point A. (And that point A is moving with the beam, so point A is always at the centre of mass).

The questions are a bit vague. I'd say you've got question 1) correct, because if it is fixed at A, then the only motion must be rotation around A.

Question 2) could mean a lot of things. The initial change in motion is clear, but then after that, it depends what direction the force is in. Is it always downwards, or does its direction change so that it is perpendicular to the axis of the beam?

For question 3), you are right that both rotational and translational motion can be caused. But I'm not sure what you mean by 'move the force along an angle, it will cause both'. And why do you think it is necessary to alter the force to cause both types of motion?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top