A flutist assembles her flute in a room where the speed of sound is 34

AI Thread Summary
The flutist's room initially has a speed of sound at 340 m/s, and she plays a note A at 440 Hz, perfectly in tune. As the air inside her flute warms, the speed of sound increases to 347 m/s. The discussion centers on calculating the beats per second she will hear when she plays the note A alongside the tuning fork. There is some confusion regarding the correct formula for beats, with participants clarifying the symbols used in the equations. Understanding the relationship between frequencies is crucial for determining the necessary adjustments to the flute's tuning joint.
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Homework Statement



A flutist assembles her flute in a room where the speed of sound is 340 m/s. When she plays the note A, it is in perfect tune with a 440 Hz tuning fork. After a few minutes, the air inside her flute has warmed to where the speed of sound is 347 .

How many beats per second will she hear if she now plays the note A as the tuning fork is sounded?

How far does she need to extend the "tuning joint" of her flute to be in tune with the tuning fork?

Homework Equations



f(beat) = 2f(mod) = 2 * (omega(mod))/(2pi) = f(1) - f(2)


The Attempt at a Solution



Ill get back with you on this
 
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I don't think it's f(1) - f(2). I think it might be f1 - f2.

In your formulas, make sure you understand what each symbol represents.
 
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