A force F is exerted on the top right corner of a rectangular plate at

AI Thread Summary
A force F is applied at a 60-degree angle to the top right corner of a rectangular plate, and the torque about point A (the lower left corner) is calculated using the components of F. The discussion emphasizes the need to split the force into its x and y components, which are F*cos(60) and F*sin(60), respectively. Participants clarify that the torque is determined by multiplying these components by their respective distances from the pivot point A. There is confusion regarding the signs of the components, as they act in opposite directions around point A, suggesting the need for a minus sign in the final torque equation. The correct expression for torque is debated, leading to the conclusion that the final answer should reflect the opposing nature of the forces.
cmkc109
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Homework Statement



A force F is exerted on the top right corner of a rectangular plate at an angle 60o
above the horizontal, as shown below. The magnitude of the torque of the force F
about point A, the lower left corner is given by

See picture please : http://tinypic.com/view.php?pic=2njv9xt&s=6


Homework Equations



Both y and x are being pulled upwards, so that is counterclockwise..
but answer is Fx sin 60 + Fy cos 60
I don't understand torque at all.. can someone please help.


The Attempt at a Solution



No idea..
 
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Hint:
 

Attachments

  • Torque.png
    Torque.png
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Thank you!
but I'm still kinda lost...
 
Last edited:
one question, where do i put the angle in?
 
I'll do a new drawing as I don't think my first was very helpful. Back soon.
 
ok thanks, check ur msg too please , thanks
 
Try this drawing. The idea is to split the force F into two component forces. Then multiply each component force by it's distance from the pivot to give two torques (Torque = force * distance). Finally you simply add the two torques.
 

Attachments

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this is the drawing i had, but from this picture, it shows that it is Fy sin 60 and Fx cos 60 , but the answer is opposite.
 
Seems ok to me.

The two components are

F*Cos(60)
F*Sin(60)

Multiply by their distance from the pivot..

y*F*Cos(60)
x*F*Sin(60)

then add.

x*F*Sin(60) + y*F*Cos(60)

Thats' the answer you gave in your first post.
 
  • #10
it still seems to be Fx cos 60 + Fy sin 60 to me :/
 
  • #11
cmkc109 said:
it still seems to be Fx cos 60 + Fy sin 60 to me :/
You need to multiply the x by the component of F that's perpendicular to it, so that's the Y component, F sin(60o).
However, none of the offered answers is correct. The X and Y components of F act in opposite sense around A, so there should be a minus sign somewhere. E.g. consider the case where y = x tan(60o). There should be no moment.
 
  • #12
The X and Y components of F act in opposite sense around A, so there should be a minus sign somewhere.

Oops I missed that.

So answer should be either...

x*F*Sin(60) - y*F*Cos(60)

or

y*F*Cos(60) - x*F*Sin(60)
 

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Last edited:
  • #13
Thank you! makes sense now
 

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