Sphere 1: +100 C Sphere 2: +1 C

In summary, the problem involves a solid, insulating sphere with a uniform charge density and a total charge Q. There is also an uncharged, conducting hollow sphere with inner and outer radii b and c. The magnitude of the electric field is being sought at two points, r=b and r=c. The charge on the inner surface of the shell will be equal and opposite to the charge of the inner sphere, which is Q. The question about the field between b and c does not require this information. In the second problem, two identical conducting spheres with net positive charges of different magnitudes are separated by a small distance. The resulting attractive force is due to polarization, which rearranges the charges and creates a stronger attraction than repulsion
  • #1
Jimmy84
191
0

Homework Statement


A solid, insulating sphere of radius a has a uniform
charge density 1 and a total charge Q. Concentric with this
sphere is an uncharged, conducting hollow sphere whose
inner and outer radii are b and c, Find the magnitude of the electric field in the
regions r=b and r= c?


Homework Equations





The Attempt at a Solution

Im stuck finding the charge there my guess is that since there is a charge one in the insulating sphere and none on the conducting one then the charge on b and on c must be 1 as well?

Im somewhat confusing, please any comment?
 
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  • #2
What's the electric field within the material of a conductor?
 
  • #3
Also I don't understand polarization at all for isntance problem 24,56 from serway

Consider two identical conducting spheres whose surfaces
are separated by a small distance. One sphere is given a
large net positive charge while the other is given a small
net positive charge. It is found that the force between
them is attractive even though both spheres have net
charges of the same sign. Explain how this is possible.

From the solutions

P24.56 The sphere with large charge creates a strong field to polarize the other sphere. That means it pushes the excess charge over to the far side, leaving charge of the opposite sign on the near side.This patch of opposite charge is smaller in amount but located in a stronger external field, so it can feel a force of attraction that is larger than the repelling force felt by the larger charge in the weaker field on the other side.

In sumary what is it that is going on in tis process can anyone please explain? Thnaks so much.
 
  • #4
Doc Al said:
What's the electric field within the material of a conductor?

zero but as far as I understand cause the charge must be zero inside a conductor. but I am concerned about the outer sides of the conductor if it is a none charged conductor then the electric field there should have the same charge of the insulating sphere isn't it?
 
  • #5
Jimmy84 said:
zero but as far as I understand cause the charge must be zero inside a conductor.
Right.
but I am concerned about the outer sides of the conductor if it is a none charged conductor then the electric field there should have the same charge of the insulating sphere isn't it?
The charge on the inner surface of the shell will be equal and opposite to the charge of the inner sphere, which is Q. But that's not needed to answer the question about the field between b and c.
 
  • #6
Doc Al said:
Right.

The charge on the inner surface of the shell will be equal and opposite to the charge of the inner sphere, which is Q. But that's not needed to answer the question about the field between b and c.

Thanks a lot, the questions of the first problem was about r=b and r=c ,not about b being less than r that is less than c.

About problem 2 how can two spehre of positive sign create an atracting force? what are the charges for the sphere that has a lot of charge, and for the one that has less charge ?

Say if the first sphere has a charge of +100 C , and the second sphere has a charge of +1 C , then what is the charge of each sphere after the polarization?
 
  • #7
Jimmy84 said:
About problem 2 how can two spehre of positive sign create an atracting force? what are the charges for the sphere that has a lot of charge, and for the one that has less charge ?

Say if the first sphere has a charge of +100 C , and the second sphere has a charge of +1 C , then what is the charge of each sphere after the polarization?
Polarization doesn't change the charge, it just rearranges them.

The like charges can be moved further away, leaving the opposite charges closer together. The resulting attraction will be greater than the repulsion, giving a net attractive force.
 

Related to Sphere 1: +100 C Sphere 2: +1 C

1. What is a Gauss sphere problem?

A Gauss sphere problem is a mathematical problem that involves determining the electric field, flux, and charge distribution of a charged sphere using Gauss's law.

2. How is Gauss's law used to solve a sphere problem?

Gauss's law states that the electric flux through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of free space. This law can be applied to a charged sphere by choosing a Gaussian surface that encloses the sphere and using the formula to calculate the electric field and flux.

3. What are the steps to solve a Gauss sphere problem?

The steps to solve a Gauss sphere problem are: choose a Gaussian surface, determine the charge enclosed by the surface, calculate the electric field using Gauss's law, and then use the electric field to calculate the flux through the surface.

4. Can the Gauss sphere problem be solved for any type of charge distribution?

Yes, Gauss's law can be applied to any type of charge distribution, including non-uniform distributions. The key is to choose an appropriate Gaussian surface that encloses the charge distribution.

5. What is the significance of solving a Gauss sphere problem?

Solving a Gauss sphere problem can provide important information about the electric field and flux of a charged sphere, which can be applied to a variety of real-world situations. It also demonstrates the usefulness and applicability of Gauss's law in solving complex problems in electromagnetism.

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