A Geometric Approach to the Standard Model, Greg Trayling

CarlB
Science Advisor
Homework Helper
Messages
1,246
Reaction score
45
A Geometric Approach to the Standard Model
Greg Trayling, Dept of Phys, U. Windsor, Windsor, Ontario
A geometric approach to the standard model of the Clifford algebra \mathcal{CL}_7 is advanced. The gauge symmetries and charge assignments of the fundamental fermions are seen to arise from a simple geometric model involving extra space-like dimensions. The bare coupling constants are found to obey g_s/g = g'/g = \sqrt{3/5} consistent with SU(5) grand unification but without invoking the notion of master groups. In constructing the Lagrangian density terms, it is found that the Higgs isodoublet field emerges in a natural manner. A matrix representation of \mathcal{CL}_7 is included as a computational aid.
http://www.arxiv.org/abs/hep-th/9912231

Also see:

A geometric basis for the standard-model gauge group
Greg Trayling, W. E. Baylis
Accepted for publication: J. Phys. A: Math. Gen. 9 Mar 2001
http://www.arxiv.org/abs/hep-th/0103137

I just found these obscure articles. My own attempts at rewriting the standard model are similar, except that I'm using preons and consequently don't need only one "extra space-like" dimension instead of the 4 used here.

Articles that cite the published article by Trayling and Baylis:
http://www.arxiv.org/abs/hep-th/0501222
http://www.arxiv.org/abs/hep-th/0412255
http://www.arxiv.org/abs/hep-th/0311045
http://www.arxiv.org/abs/gr-qc/0212041
http://www.arxiv.org/abs/hep-th/0203122

Carl
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top