- #1
chris99191
- 9
- 0
1. First one is (sin2x+sinx)/(cos2x+cosx+1)=tanx
Second one is (sec∂-tan∂)²=(1-sin∂)/(1+sin∂)
2. Sec=1/cos tan=sin/cos cos²x+sin²x=1
3. 1. I think eventually the sinx/cosx need to cancel to make tanx and the 1 could be used to create a lot of options
2. I have tried to start with the left hand side. However i am unsure whether to expand the bracket or not. I've tried it with 1/cos but I couldn't get very far
Second one is (sec∂-tan∂)²=(1-sin∂)/(1+sin∂)
2. Sec=1/cos tan=sin/cos cos²x+sin²x=1
3. 1. I think eventually the sinx/cosx need to cancel to make tanx and the 1 could be used to create a lot of options
2. I have tried to start with the left hand side. However i am unsure whether to expand the bracket or not. I've tried it with 1/cos but I couldn't get very far