A heat engine and determining Power

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To determine the power required by the heat engine to lift a 10 kg mass at a constant speed of 4 meters per second, the work done can be calculated using the formula w = m g Δh, where g is the acceleration due to gravity and Δh is the height lifted. The work done in lifting the mass must be calculated first, which will then provide the power output in watts when divided by the time taken (one second). The discussion highlights the importance of recognizing key terms in physics problems, such as "per second," which are crucial for solving them accurately. The operating temperatures of the heat engine, 500K and 300K, may also play a role in further calculations, though they are not directly addressed in this initial power calculation. Understanding these principles is essential for effectively applying thermodynamic concepts to practical scenarios.
JasonL
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A heat engine operating between temperatures 500K and 300K is used to lift a 10KG mass vertically at a constant speed of 4 meters per second.

Determine the power the engine must supply to life the mass.


I'm having trouble finding an equation that could relate temperature and my other given variables..I think I need to get the Work done, thus I can calculate the power...anyone care to enlighten me as to how to go about it?
 
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Hint: How much work is required to lift a 10 kg mass 4 m? Since the engine must produce that much work every second, how much power must it supply?

(I assume there is more to this question. Other parts will make use of the operating temperatures.)
 
You assume correctly(But I can do the rest myself), often times when reading a physics question over and over you still miss little things such as "per second", that are the keys to helping you solve a problem...Thanks Doc

I even typed it...sheesh...
 
w = m g \Delta h
You'll get this in joules, times that one second gives you watts.
 
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