A high diver jumping off a board (basic force problem)

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A high diver with a mass of 50.0 kg jumps from a height of 10.0 m, hitting the water with a final velocity of 14 m/s. The average acceleration during her deceleration in the water is calculated to be approximately 6.09 m/s². The force exerted by the water on the diver is computed as 304.35 N. However, the answer was marked incorrect, possibly due to the expected sign convention for acceleration. Clarification from the professor regarding the negative sign for upward acceleration is recommended.
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Homework Statement



A high diver of mass 50.0 kg jumps off a board 10.0 m above the water. If her downward motion is stopped 2.30 s after she enters the water, what average force did the water exert on her?


Homework Equations



Fnet=ma
vf2=v02+2ax

The Attempt at a Solution



First I found the final velocity of the diver when she hits the water

vf2=02+2(9.8)(10)=196

vf=14 m/s

Since she is slowed to a stop in 2.3s the average acceleration would be

14/2.3 = 6.08696

Knowing acceleration and her mass, we can calculate the force.

F=50(6.08696)=304.348

This answer was marked wrong. I'm pretty sure I did everything right. Am I missing something?
 
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Your calculation is correct for the magnitude of the acceleration. Maybe the dumb machine that marked this problem expected a negative sign in front of the acceleration. I say "dumb" because the acceleration is in the "up" direction which is conventionally positive. You may have to ask your teacher for a clarification of this point.
 
Thanks for your input, I'll be sure to ask my professor about this problem.
 
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