A horizontal force of 100 N is applied a block solve this

AI Thread Summary
A horizontal force of 100 N applied to a block on a frictionless surface results in an acceleration of 3 m/s². The mass of the block is calculated as 33.33 kg using the formula mass = force/acceleration. If the force is applied for 10 seconds, the block will travel a distance of 150 meters, determined by the equation distance = 1/2 * acceleration * time². After 10 seconds, the speed of the block will reach 30 m/s, calculated with velocity = acceleration * time. Overall, the calculations are confirmed to be correct, aside from an initial unit error regarding mass.
wein7145
Messages
19
Reaction score
0

Homework Statement


1) A block lies on a horizontal friction-less surface. A horizontal force of 100 N is applied to the block giving rise to an acceleration of 3m/s^2.

(a) Determine the mass of the block.
b)Calculate the distance the block will travel if the force is applied for 10s.
c)Calculate the speed of the block after the force has been applied for 10s.

Homework Equations


Force=mass*(acceleration)
distance = 1/2*a*t^2
velocity = a*t

The Attempt at a Solution


a) I'm pretty sure it's just Force/accel =mass so 100N/3m/s^2=33.33kg (Edit kg not N)
b) distance = 1/2*a*t^2 = 1/2*3 m/s^2 * (10s)^2 = 150 m
c) velocity = a*t = 3 m/s^2 * 10s = 30 m/s
Just check over my work. At least I feel like I'm learning something this week.
 
Last edited:
Physics news on Phys.org
wein7145 said:

Homework Statement


1) A block lies on a horizontal friction-less surface. A horizontal force of 100 N is applied to the block giving rise to an acceleration of 3m/s^2.

(a) Determine the mass of the block.
b)Calculate the distance the block will travel if the force is applied for 10s.
c)Calculate the speed of the block after the force has been applied for 10s.

Homework Equations


Force=mass*(acceleration)
distance = 1/2*a*t^2
velocity = a*t

The Attempt at a Solution


a) I'm pretty sure it's just Force/accel =mass so 100N/3m/s^2=33.33N
b) distance = 1/2*a*t^2 = 1/2*3 m/s^2 * (10s)^2 = 150 m
c) velocity = a*t = 3 m/s^2 * 10s = 30 m/s
Just check over my work. At least I feel like I'm learning something this week.

In a) the units of mass are not Newtons.
 
  • Like
Likes wein7145
In a) the units of mass are not Newtons.
Whoops your right they are kg (Kilograms) But does everything else look good?
 
wein7145 said:
Whoops your right they are kg (Kilograms) But does everything else look good?
Yes, everything else seems to be OK.
 
  • Like
Likes wein7145
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top