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A little confused

  1. Jan 26, 2006 #1
    why does det(kA)=(k^n)detA and not kdetA?
  2. jcsd
  3. Jan 26, 2006 #2

    Meir Achuz

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    The matrlix kA has a factor of k in every element. Each term in the determinant of an nXn matrix has n factors, so k comes in n times.
    Therefore, det(kA)=k^n det(A).
  4. Feb 6, 2006 #3
    thank you very much!!!
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