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- Summary
- As hawking radiation is based on quantum fluctuations, can they cancel out each other due to equal probabilities of a particle remaining in or drifting away?

**Summary:**As hawking radiation is based on quantum fluctuations, can they cancel out each other due to equal probabilities of a particle remaining in or drifting away?

I recently learned how hawking radiation actually works. It is based on quantum fluctuations which happen

*randomly*in space. So when one of them happens on the edge of a black hole's event horizon, there is a chance that the anti-particle drifts away and the particle stays inside or gets pulled inside the black hole, and the opposite can happen too. This results in an extra particle or anti-particle which annihilates the opposite part inside the black hole.

So, shouldn't there be an equal chance of a particle drifting away or getting pulled in by the black hole? In each case, the opposite would happen to the anti-particle. So, suppose that in an instance two fluctuations happened at the edge of event horizon. In the first one the particle drifted away and in the second one, the anti-particle drifted away. So that leaves one particle and anti-particle outside the black hole, and one set inside. So, both sets can cancel out each other and the particle or anti-particle inside the black hole won't annihilate an

*extra*particle or anti-particle.

This means that hawking radiation shouldn't happen, logically.

I might have made a big error in this, as I don't know a lot about physics. But, please correct me if you find any mistake (which there surely must be). Thanks for reading!