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A moving charged particle

  1. Dec 2, 2012 #1
    1. The problem statement, all variables and given/known data

    2eohano.jpg

    kdjzvc.jpg

    I already worked out the right hand side. What is giving me problems is figuring out the left hand side, ∫Bdl

    Since B is uniform, it can be removed from the integral leaving B∫dl

    now i'm stuck.





    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Dec 2, 2012 #2

    TSny

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    ∫dl is just the sum of all the elements of length around the circle of radius R. Your work up to this point looks good to me.
     
  4. Dec 2, 2012 #3
    in that case would it simply be 2pir?
     
  5. Dec 2, 2012 #4

    TSny

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    Yes, with r = R.
     
  6. Dec 2, 2012 #5
    Thanks TSny.
     
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