DrChinese
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For those of you interested in some of the more specific ideas behind the general Entanglement Swapping protocol, I will run through a rough example.
1. Keep in mind that the time/distance traveled can be relatively lengthened or shortened by adding fiber to one part of the overall setup or the other.
a) So the independent sources I and II can be kilometers apart.
b) Alice (observing photon 1 from PDC source I) and Bob (observing photon 4 from PDC source II) can be kilometers apart.
c) Each of those can be kilometers away from their source.
d) And Chris can be located such that Chris' decision to enable entanglement (via the swap mechanism, called a Bell State Measurement or BSM) can occur before or after the detectors of Alice and Bob click. Let's keep it simple, and have the BSM/swap positioned to occur before Alice and Bob see their clicks.
2. What needs to be synchronized?
a) The laser sources driving their respective PDC crystals must be phase locked.
b) The difference in the photon travel time from source I for photon 1 as compared to the photon travel time from source II for photon 4 should be known. This is to match an Alice click with a Bob click, indicating 2 of the 4 fold coincidence clicks we are looking for. That time difference is used to compensate for relative travel distance. The 1 & 4 photons don't need to actually arrive at their respective detectors at exactly the same time if this difference is known.
c) The difference in the photon travel time from source I for photon 1 as compared to the photon travel time from source I for photon 2 should be known. This allows for 3 fold coincidence detection.
d) The difference in the clicks of Chris's detectors (there are 4) must be known. If these do not occur within a sufficiently small time window, there can be no swap.
3. A single PDC source might randomly emit entangled pairs at the rate of perhaps 100,000 per second, or about 1 every 10,000 nanoseconds. We need the 2 & 3 photons - coming at random times from the two phase locked sources I and II to arrive within a narrow time window, such that the arrival time of its initial entangled partner (1 or 4) would not give us a clue as to which is which (they must be indistinguishable). Let's pretend that window is 5 nanoseconds. That means that on the average, sources I and II emit pairs that will ultimately overlap (at random intervals) within our desired time window of about 1 in 2,000 of each of those 100,000. That would be about 5,000 per second (this number is not particularly accurate, we are just for this example).
a) We would expect 2 fold coincidences (for 1 & 2, or 3 & 4) of about 200,000 per second, as most of the time the source I and source II pairs would not fire close enough together to be within the 5 nanosecond window.
b) We would expect 3 or 4 fold coincidences - for 1 & (2 or 3) & 4 - of about 5,000 per second, whenever the the source I and source II pairs do fire close enough together to be within the 5 nanosecond window.
c) We would expect 4 fold coincidences (for 1 & 2 & 3 & 4) of about 2,500 per second, whenever the the source I and source II pairs do fire close enough together to be within the 5 nanosecond window... AND the Bell state is identifiable. This occurs half of the time of the b) group above.
4. Keep in mind that ALL of the identifiable c) cases are considered in our results. Half of the b) cases are not used because the Bell state cannot be identified. That does NOT mean those cases were not entangled - all 5,000 per second are entangled. But half of those are φ+ or φ- entangled, and we can't distinguish between those - because both the 2 & 3 photons end up in the same detector (yielding only 1 click for the two photons). Only the ψ+ and ψ- can be identified (because the 2 & 3 photons end up in different detectors, yielding 2 clicks).
It is essential that the clicks from the 2 & 3 photons cannot provide any information as to which click is photon 2, versus which click is photon 3. That is why close arrival time is needed. And when I say close arrival time - as indicated by detector clicks: I really mean that photon 2 and photon 3 travel through the beam splitter portion of the BSM swapping mechanism close enough in time that they are allowed to interact. Because if photon 3 is delayed sufficiently such that there is no close overlap, photons 2 & 3 become distinguishable. That would be evident by one click alone arriving late, identifying photon 3. Then no swap will occur.
I hope these details will help some readers understand exactly what these experiments are demonstrating. Everything presented is orthodox QM.
1. Keep in mind that the time/distance traveled can be relatively lengthened or shortened by adding fiber to one part of the overall setup or the other.
a) So the independent sources I and II can be kilometers apart.
b) Alice (observing photon 1 from PDC source I) and Bob (observing photon 4 from PDC source II) can be kilometers apart.
c) Each of those can be kilometers away from their source.
d) And Chris can be located such that Chris' decision to enable entanglement (via the swap mechanism, called a Bell State Measurement or BSM) can occur before or after the detectors of Alice and Bob click. Let's keep it simple, and have the BSM/swap positioned to occur before Alice and Bob see their clicks.
2. What needs to be synchronized?
a) The laser sources driving their respective PDC crystals must be phase locked.
b) The difference in the photon travel time from source I for photon 1 as compared to the photon travel time from source II for photon 4 should be known. This is to match an Alice click with a Bob click, indicating 2 of the 4 fold coincidence clicks we are looking for. That time difference is used to compensate for relative travel distance. The 1 & 4 photons don't need to actually arrive at their respective detectors at exactly the same time if this difference is known.
c) The difference in the photon travel time from source I for photon 1 as compared to the photon travel time from source I for photon 2 should be known. This allows for 3 fold coincidence detection.
d) The difference in the clicks of Chris's detectors (there are 4) must be known. If these do not occur within a sufficiently small time window, there can be no swap.
3. A single PDC source might randomly emit entangled pairs at the rate of perhaps 100,000 per second, or about 1 every 10,000 nanoseconds. We need the 2 & 3 photons - coming at random times from the two phase locked sources I and II to arrive within a narrow time window, such that the arrival time of its initial entangled partner (1 or 4) would not give us a clue as to which is which (they must be indistinguishable). Let's pretend that window is 5 nanoseconds. That means that on the average, sources I and II emit pairs that will ultimately overlap (at random intervals) within our desired time window of about 1 in 2,000 of each of those 100,000. That would be about 5,000 per second (this number is not particularly accurate, we are just for this example).
a) We would expect 2 fold coincidences (for 1 & 2, or 3 & 4) of about 200,000 per second, as most of the time the source I and source II pairs would not fire close enough together to be within the 5 nanosecond window.
b) We would expect 3 or 4 fold coincidences - for 1 & (2 or 3) & 4 - of about 5,000 per second, whenever the the source I and source II pairs do fire close enough together to be within the 5 nanosecond window.
c) We would expect 4 fold coincidences (for 1 & 2 & 3 & 4) of about 2,500 per second, whenever the the source I and source II pairs do fire close enough together to be within the 5 nanosecond window... AND the Bell state is identifiable. This occurs half of the time of the b) group above.
4. Keep in mind that ALL of the identifiable c) cases are considered in our results. Half of the b) cases are not used because the Bell state cannot be identified. That does NOT mean those cases were not entangled - all 5,000 per second are entangled. But half of those are φ+ or φ- entangled, and we can't distinguish between those - because both the 2 & 3 photons end up in the same detector (yielding only 1 click for the two photons). Only the ψ+ and ψ- can be identified (because the 2 & 3 photons end up in different detectors, yielding 2 clicks).
It is essential that the clicks from the 2 & 3 photons cannot provide any information as to which click is photon 2, versus which click is photon 3. That is why close arrival time is needed. And when I say close arrival time - as indicated by detector clicks: I really mean that photon 2 and photon 3 travel through the beam splitter portion of the BSM swapping mechanism close enough in time that they are allowed to interact. Because if photon 3 is delayed sufficiently such that there is no close overlap, photons 2 & 3 become distinguishable. That would be evident by one click alone arriving late, identifying photon 3. Then no swap will occur.
I hope these details will help some readers understand exactly what these experiments are demonstrating. Everything presented is orthodox QM.