martinbn said:
1. Ok, but then you need to look at the corresponding cards in 1 and 4. Say Chris picked the 5th card in 2 and the 10th card in 3. Then the 5th card in 1 and the 10th in 4 will be correlated.
2. If this is not what you mean then run the experiment with specific outcomes, so that I can see what the challenge is.
1. Chris has no communication from anyone about what N is, i.e. selecting the Nth card. That's because in a Bell State Measurement (BSM) on photons (card decks) 2 & 3, the angle settings are held constant and do not change from trial to trial. The information gained from the BSM indicates a ψ+ (colors of 2 & 3 match in the analogy) or ψ- (2 & 3 don't match in the analogy).
The real BSM actually operates like this, just so you can see that there is no useful information gained as to the specific outcomes that will be seen by Alice (photon 1) and Bob (photon 4):
a) The 2 & 3 photons must overlap in time (i.e. be indistinguishable) at a beam splitter (BS), and they can either come out the same ports or different ports of the BS. Whether you have ψ+ or ψ-: one will always be vertically polarized |V> and the other will always be horizontally polarized |H>. They are therefore always orthogonal, and in principle should never directly interact.
b) Each output port of the single BS has a polarizing beam splitter (PBS) and 2 detectors at their output ports - one for the |V> and one for the |H>. So 1 BS, 2 PBSs and 4 detectors in total for the BSM. The angle orientation of the 2 PBSs are the same, but bears no specific relationship to anything happening with Alice's and Bob's settings. Again, this is held fixed from trial to trial.
c) If both detectors click on one side (the same output port of the BS), the resulting Bell state is ψ+. If they show up on different sides of the BS, the resulting Bell state is ψ-. ψ+ means the Alice and Bob outcomes will correlate perfectly at any same angle setting selected for them. ψ- means the Alice and Bob outcomes will anti-correlate perfectly at any same angle setting. In other words: since the polarization outcomes of 2 & 3 are always |HV> or |VH> (indistinguishable), their polarization makes no difference to learning whether there will be correlation or anti-correlation for Alice and Bob. It is whether the 2 & 3 photons appear on the same side - or different sides - of the BS output ports that determines that.
Now, this entire BSM process cannot be mapped directly to any card decks. So I am merely modeling it as if Chris in Paris essentially picks 2 random cards and therefore gets a random outcome - which we then associate with ψ+ or ψ-. And a random outcome is precisely what the actual BSM produces!
2. Sure.
a) Alice (decks 1 & 2, these are to be alike) and Bob (decks 3 & 4, also to be alike) shuffle (or otherwise arrange) their decks independently.
b) They send decks 2 & 3 to Chris, who does "something" which produces a + or - result, without knowing anything about how Dale will select N (the Nth card from each of decks 1 & 4). Let's say Chris see different colors (Red from deck 2, Black from deck 3) and calls that a "-" (which would be ψ-). Note again, this is simply a random outcome of whatever Chris does, just like the outcome of a real BSM is random.
c) Chris sends her "-" result to Dale. Dale then selects N=37 (which neither Alice nor Bob knew in advance). He gets the color of Alice's 37th card. It is Red. Dale immediately know that Bob's 37th card will be Black, because Chris' "-" results means anti-correlated on Alice/Bob colors.
d) More trials might look like this:
Chris "+", Dale N=12, Alice=Red, Bob=Red (as Dale predicted).
Chris "+", Dale N=49, Alice=Black, Bob=Black (as Dale predicted).
Chris "-", Dale N=49, Alice=Black, Bob=Red (as Dale predicted).
Chris "+", Dale N=20, Alice=Black, Bob=Black (as Dale predicted).
Chris "-", Dale N=12, Alice=Red, Bob=Black (as Dale predicted).
Chris "-", Dale N=32, Alice=Black, Bob=Red (as Dale predicted).
How can Dale make good predictions when Alice in Lille and Bob in Lyon don't know what each other are doing; Chris does not know N (which is selected by remote Dale) and is merely reporting a random "+" or "-"?
Each of Dale's successful predictions are the EPR definition of an "element of reality". Alice's measurement could not have affected Bob's outcome if local causality holds - they are distant. In the original EPR, they believed that such an element of reality occurred because the Alice and Bob particles had interacted in the past, and there would be conservation rules at play. Therefore the result of any measurements on Alice and Bob must be predetermined (at least that's what their logic told them).
In my "modern" version of EPR: There is an element of reality in each trial, just as in the original. But... the Alice and Bob particles had NEVER interacted in the past. So there is no conservation rules at play to explain the observed correlation/anti-correlation. That is replaced by Chris' Bell State Measurement, which is the "cause" of the swap. Chris is too far away from all of the others for the outcome of Chris' BSM to affect the outcomes of Alice and Bob's measurement, if local causality* holds.
- Bohmian explanation: There is explicitly nonlocality, so locality** fails.
- Relational Blockworld ( @RUTA hopefully you agree here) : Reality is "acausal", so causality* fails.
- Orthodox QM: Quantum nonlocality mechanism is not specified in the theory, but locality** and/or causality* fails and the theoretical predictions are upheld.
*Causality meaning: there is a) an identifiable cause which is separate from its effect; and b) the cause must precede the effect.
** Locality meaning: no physical influence can propagate or otherwise connect space-like separated particles or events.