A particle of mass m moves in a one dimensional potential

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A particle of mass m is analyzed in a one-dimensional potential U(x)=A|x|^3, with the time period T related to total energy E by T=E-1/k. The equations of motion include kinetic energy and potential energy, with the force defined as F=-dU/dx. The velocity is expressed as v=√(2/m(E-A|x|^3)), and the time differential dt is derived from dx/v. The challenge lies in determining the integration limits for calculating the time period, which correspond to the turning points where potential energy equals total energy. The discussion focuses on finding the constant k in the time period equation.
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1.The problem, statement, all variables and given/known data

A particle of mass m moves in a one dimensional potential U(x)=A|x|3, where A is a constant. The time period depends on the total energy E according to the relation T=E-1/k
Then find the value of k.

2. Homework Equations


V=dx/dt
E=kinetic energy + U
F=-dU/dx

The Attempt at a Solution



##E=\frac{1}{2}mv^2+a|x|^n##
##v=\sqrt{\frac{2}{m}(E-a|x|^n)}##
##dt=\frac{dx}{v}##
Integrating LHS, I can get the time period. But when integrating RHS, how do I find the limits?
 
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The particle moves between the turning points, where its velocity becomes zero, that is, the potential energy is equal to the total energy E.
 
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