A person moves a full sam's club shopping cart mass=80.0 kg from rest

  • Thread starter Thread starter Ereny
  • Start date Start date
  • Tags Tags
    Cart Rest
AI Thread Summary
To find the time required to accelerate an 80 kg shopping cart from rest to 1.30 m/s over 1.80 meters, the acceleration can be calculated using kinematic equations. The change in momentum of the cart is determined by multiplying its mass by the final velocity. The force exerted by the person can be calculated using Newton's second law, factoring in the acceleration found earlier. When considering friction with a coefficient of 0.40, the force required to move the cart includes both the applied force and the frictional force, which is calculated using the normal force. Understanding these principles allows for a comprehensive analysis of the forces involved in moving the cart.
Ereny
Messages
29
Reaction score
0
a person moves a full sam's club shopping cart mass=80.0 kg from rest to a velocity of 1.30 m/s over a distance of 1.80 meters to secure a spot in check out line.

A. find the time required to get the cart moving from rest to 1.30 m/s?

B. Determine the change in the chart's momentum?

c. determine the magnitude of the force exerted on the cart by the person.

D. the result from part c ignores friction. if the shopping cart's coefficient of friction is .40 determine the force required by the person to move the cart. (recall the friction force = UFn)
 
Physics news on Phys.org
Hi Ereny! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Coefficient of Friction question for a cart going down a wooden ramp
Replies
18
Views
3K
Impulse and Momentum: Ball and cart connected by a cord
Replies
24
Views
3K
Acceleration of a cart immediately after the system is released
Replies
15
Views
4K
Momentum with Two Carts on a Low-Friction Track
Replies
3
Views
5K
Cart/putty collision question (conservation of momentum)
Replies
6
Views
6K
Two Carts attached to a string
Replies
5
Views
8K
Average Force of two people pushing away on carts
Replies
11
Views
3K
How Far Will the Ball Roll Relative to the Ground in 0.10 Seconds?
Replies
12
Views
5K
Cart with 2 springs and a sliding mass
Replies
20
Views
2K
How do you find acceleration using Hooke's law?
Replies
3
Views
10K

Hot Threads

Recent Insights

Back
Top