A pilot makes a series of loop-the-loops.

  • Thread starter Thread starter mali200
  • Start date Start date
  • Tags Tags
    Series
AI Thread Summary
At the bottom of a loop-the-loop, the normal force on the pilot is greater than the force of gravity due to the centripetal acceleration required to maintain the circular motion. The normal force acts upward, countering gravity and providing the necessary net force for the pilot's circular path. Without specific values for acceleration, it is challenging to determine the exact magnitudes of the forces involved. Participants in the discussion emphasize the importance of showing attempts at solving the problem to receive assistance. Understanding the dynamics of forces in circular motion is crucial for accurately answering the question.
mali200
Messages
1
Reaction score
0
Can you please help in the following question;

A pilot makes a series of loop-the-loops. At the bottom of one of the circular loops, the normal force on the pilot is ------------------. List all that apply in alphabetical order;
a) Of lesser magnitude than the force of gravity
b) Of equal magnitude to the force of gravity
c) Of greater magnitude than force of gravity
d) Impossible to tell the relative magnitude since the acceleration value is not explicitly stated
e) Directed upward
f) Directed downward
g) No-existent

Thanks
 
Physics news on Phys.org


mali200 said:
Can you please help in the following question;

A pilot makes a series of loop-the-loops. At the bottom of one of the circular loops, the normal force on the pilot is ------------------. List all that apply in alphabetical order;
a) Of lesser magnitude than the force of gravity
b) Of equal magnitude to the force of gravity
c) Of greater magnitude than force of gravity
d) Impossible to tell the relative magnitude since the acceleration value is not explicitly stated
e) Directed upward
f) Directed downward
g) No-existent

Thanks
Hello mali200. Welcome to PF !

According to the rules for Homework Help on these Forums:
NOTE: You MUST show that you have attempted to answer your question in order to receive help. You MUST make use of the homework template, which automatically appears when a new topic is created in the homework help forums.​
So, what do you think the answer is -- more importantly, why do you think that's the answer ?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top