A problem about a moving nickel coin - help/advice

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A nickel coin with a diameter of 2 cm and thickness of 2 mm rolls at 10 cm/s and encounters an incline after 55.2 cm, needing to reach a maximum height of 0.5 mm. The problem involves calculating the maximum angle of inclination, factoring in a constant friction force of 7.5 micro Newtons. The conservation of energy and Newton's laws are the primary equations to apply. The initial calculation yielded an angle of approximately 40 degrees, but the poster suspects an error. Further clarification and detailed attempts at the solution are encouraged for effective assistance.
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Please, help me with this:

Homework Statement


A nickel coin with diameter 2 cm and thickness 2 mm starts to roll with no friction on a horizontal plane with spped 10 cm/s. At 55.2 cm from the beginning the plane is inclined up. For the coin to go up to height max= 0.5 mm, what should be the maximum angle of inclination ? The rotation frequency is 1/2pi (s^-1), and the friction force down the inclined region is constand with f = 7.5 mikro Newtons.

also, the nickle density is 8.9 g/cubic cm

Homework Equations



conservation of energy, Newton's laws, laws of mechanical motion

The Attempt at a Solution



I receive an angle of ~40 degree, but I think something's wrong. Thanks for the advice!
 
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Welcome to PF!

Hi archivlad! Welcome to PF! :smile:

(have a mu: µ and a pi: π :wink:)
archivlad said:
A nickel coin with diameter 2 cm and thickness 2 mm starts to roll with no friction on a horizontal plane with spped 10 cm/s. At 55.2 cm from the beginning the plane is inclined up. For the coin to go up to height max= 0.5 mm, what should be the maximum angle of inclination ? The rotation frequency is 1/2pi (s^-1), and the friction force down the inclined region is constand with f = 7.5 mikro Newtons.

also, the nickle density is 8.9 g/cubic cm

conservation of energy, Newton's laws, laws of mechanical motion

Yup … conservation of energy is the way to go!

Show us what you tried, and where you're stuck, and then we'll know how to help. :smile:
 
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