A problem Simple harmonic motion

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SUMMARY

The discussion focuses on calculating the frequency of oscillation for a particle of mass 10g in a potential field defined by V = (50x² + 100) erg/g. The correct formula for frequency is n(frequency) = 2π(K/m)¹/². The user initially calculated K as 100, leading to an angular frequency of 10¹/², but the textbook states the angular frequency should be 100¹/². The discrepancy arises from the need to convert units from erg to joules and grams to kilograms for accurate calculations.

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harini07
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Homework Statement


A particle of mass 10g is placed in potential field given by V= (50x^2+100)erg/g. what will be the frequency of oscillation?

Homework Equations


n(frequency)=2pi(K/m)^1/2

The Attempt at a Solution


F= -dU/dx . given is potential field. so dU/dx= (2*50x +0)=-100x. equating it with -Kx(since F= -Kx) , K=100. so omega(angular frequency)=(K/m)^1/2= (100/10)^1/2= 10^1/2. but the answer as given in the key of my textbook is 100^1/2 for angular frequency, hows that possible? where did i go wrong?
 
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harini07 said:

Homework Statement


A particle of mass 10g is placed in potential field given by V= (50x^2+100)erg/g. what will be the frequency of oscillation?

Homework Equations


n(frequency)=2pi(K/m)^1/2

The Attempt at a Solution


F= -dU/dx . given is potential field. so dU/dx= (2*50x +0)=-100x. equating it with -Kx(since F= -Kx) , K=100. so omega(angular frequency)=(K/m)^1/2= (100/10)^1/2= 10^1/2. but the answer as given in the key of my textbook is 100^1/2 for angular frequency, hows that possible? where did i go wrong?
You need to convert erg into joule and gram into kilogram.
 
cnh1995 said:
You need to convert erg into joule and gram into kilogram.
even then I'm unable to arrive at the answer :/ erg/g in J/kg will be 10^-4 .how to proceed?
 

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