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A problem Simple harmonic motion

  1. Dec 14, 2016 #1
    1. The problem statement, all variables and given/known data
    A particle of mass 10g is placed in potential field given by V= (50x^2+100)erg/g. what will be the frequency of oscillation?

    2. Relevant equations
    n(frequency)=2pi(K/m)^1/2

    3. The attempt at a solution
    F= -dU/dx . given is potential field. so dU/dx= (2*50x +0)=-100x. equating it with -Kx(since F= -Kx) , K=100. so omega(angular frequency)=(K/m)^1/2= (100/10)^1/2= 10^1/2. but the answer as given in the key of my text book is 100^1/2 for angular frequency, hows that possible? where did i go wrong?
     
  2. jcsd
  3. Dec 14, 2016 #2

    cnh1995

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    Homework Helper

    You need to convert erg into joule and gram into kilogram.
     
  4. Dec 14, 2016 #3
    even then i'm unable to arrive at the answer :/ erg/g in J/kg will be 10^-4 .how to proceed?
     
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