1. The problem statement, all variables and given/known data A particle of mass 10g is placed in potential field given by V= (50x^2+100)erg/g. what will be the frequency of oscillation? 2. Relevant equations n(frequency)=2pi(K/m)^1/2 3. The attempt at a solution F= -dU/dx . given is potential field. so dU/dx= (2*50x +0)=-100x. equating it with -Kx(since F= -Kx) , K=100. so omega(angular frequency)=(K/m)^1/2= (100/10)^1/2= 10^1/2. but the answer as given in the key of my text book is 100^1/2 for angular frequency, hows that possible? where did i go wrong?