A puck slides a total of 12m: Problem relating kinteic friction to Newton's law

AI Thread Summary
The problem involves calculating the initial speed of a puck that slides 12 meters on a shuffleboard before stopping, with a coefficient of kinetic friction of 0.28. To find the acceleration, Newton's second law can be applied without needing the puck's mass, as it cancels out in the equations. The equation v^2 - v_0^2 = 2as is used, where the final velocity is zero after traveling the distance. By substituting the calculated acceleration into the equation, the initial speed can be determined. The solution emphasizes the importance of recognizing how mass cancels in the calculations.
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Homework Statement



In a shuffleboard game, the puck slides a total of 12 m before coming to rest. If the coefficient of kinetic friction between the puck and board is 0.28, what was the initial speed of the puck?

Homework Equations


f=ma
fk=U*N
vf^2=v^2+2ad
a=delta v/t


The Attempt at a Solution



I tried to find the acceleration using the equation above but since I don't know the initial speed, I get 2 unknown. I tried to substitute a by delat v/t but I don't have time either. I don't have the mass of the puck either so I can't find the normal force. How can I start?
 
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Use Newton's 2nd law to find the acceleration. (You don't need the actual mass--just call it m.)
 
From Newton's law: you can find accleration of puck.
P + Ff + N = ma

After find a, you will use this eq:
v^2 - v_0^2= 2as

Because puck is at rest after going distance = 12m, v = 0. Plug a, then you get answer.
 
Thanks to both of you, I got it! I didn't see the masses canceled in the first equation.
 
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