Find a point P on y=x3 such that the tangent at P intersects the original curve again at point Q so that the slope of the tangent at Q is 4 times the slope of the tangent at P.
and the slope of the what I think it should be a secant line=(y2-y1)/(x2-x1)
The Attempt at a Solution
I figured that 2P=Q because 3P2=(3/4)Q2 and then by using algebra I expressed Q in terms of P.
I know this leads to somewhere, but im not sure what should I do next.