A question about common emitter amplifier

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Homework Help Overview

The discussion revolves around the role of the blocking capacitor in a common emitter amplifier circuit, particularly focusing on the relationship between the capacitor value and the voltage divider resistors. Participants are exploring the implications of the equation C >= 1/2πf(R1||R2) as presented in a textbook.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the factors that influence the input impedance of the circuit and the specific relationship between the blocking capacitor and the voltage divider resistors. There are inquiries about the functions of the blocking capacitor and how to calculate its value based on frequency and impedance.

Discussion Status

Some participants have provided insights into the functions of the blocking capacitor, noting its role in blocking DC and allowing AC to pass, as well as serving as a high-pass filter. There is an ongoing exploration of how to calculate the capacitor value and what factors it depends upon, with references to the equation mentioned.

Contextual Notes

Participants are working with a specific frequency of 200Hz and an input impedance of 8kOhms, which may influence their calculations and understanding of the capacitor's role in the circuit.

Harrison G
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Homework Statement


Hello my fellow PF mates! Today i received my electronic textbook from Russia. The book is great, however i can't explain myself one single equation, but i hope you will help me:-)

The question is about the blocking capacitor in a common emitter amplifier. R1 and R2 are the voltage divider resistors (sorry, but i still haven't learned how to post images) and C is the blocking capacitor.
There is one relationship that i can't figure out.

Homework Equations


The textbook says that when choosing C, C>= 1/2пf(R1||R2)
My question is why C should be equal or greater then 1/2пf(R1||R2)?

The Attempt at a Solution

 
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What are the major contributing factors to the input impedance of the circuit?
 
gneill said:
What are the major contributing factors to the input impedance of the circuit?
The input impedance is 8kOhms and the frequency is 200Hz, for this is used a capacitor of 0.1uF
 
Harrison G said:

Homework Statement


Hello my fellow PF mates! Today i received my electronic textbook from Russia. The book is great, however i can't explain myself one single equation, but i hope you will help me:-)

The question is about the blocking capacitor in a common emitter amplifier. R1 and R2 are the voltage divider resistors (sorry, but i still haven't learned how to post images) and C is the blocking capacitor.
There is one relationship that i can't figure out.

Homework Equations


The textbook says that when choosing C, C>= 1/2пf(R1||R2)
My question is why C should be equal or greater then 1/2пf(R1||R2)?

The Attempt at a Solution

What are the two functions of the input DC blocking capacitor in the CE amplifier circuit?

http://webpages.ursinus.edu/lriley/ref/circuits/img119.gif
img119.gif
 
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berkeman said:
What are the two functions of the input DC blocking capacitor in the CE amplifier circuit?

http://webpages.ursinus.edu/lriley/ref/circuits/img119.gif
img119.gif
As far as i know, the blocking capacitor have 2 main uses. 1st they block DC and allow only AC to pass and 2nd they incidentaly serve as a high pass filter and must be calculated for the working frequency so that they don't cause any trouble. But as i see now, maybe i didnt formulated correctly my question -- How do we calculate that capacitor and what its value depends upon?
 
Harrison G said:
As far as i know, the blocking capacitor have 2 main uses. 1st they block DC and allow only AC to pass and 2nd they incidentaly serve as a high pass filter and must be calculated for the working frequency so that they don't cause any trouble. But as i see now, maybe i didnt formulated correctly my question:How do we calculate that capacitor and what its value depends upon?
Correct. So to be a HPF, that input C and the two input base bias resistors have to have a certain relationship. And it looks like that relationship is the equation you posted in your first post... :smile:
 
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berkeman said:
Correct. So to be a HPF, that input C and the two input base bias resistors have to have a certain relationship. And it looks like that relationship is the equation you posted in your first post... :smile:
Thank you verry much for youre help! :-)
 
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